Find the exact value of tan ^-1 (-root of 3) Write your answer in radians in terms of n.

Mathematics

1 answer:

mamaluj [8]3 years ago

8 0

Answer:

To find the exact vale of atan(-sqrt(3)) we're going to need the help of a calculator

atan(-sqrt(3)) = -1.04719755 rads.

If you take a look at the important angles, you will notice that the arc is minus 60 degrees which equals -1.04716755 radians.

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La pregunta en la imagen

dusya [7]

Answer:

216mx meters

Step-by-step explanation:

m is in minutes so convert it in hours = 60m hrs

Speed is in metres per second, convert it in kilometers per hour= 18x/5

Now we’ve time and speed, put it in the formula

Distance = speed x time

= 18x/5 x 60m

= 216mx meters

Hope it helps

6 0

2 years ago

What is the answer to this?

snow_tiger [21]

Answer:

it cannot be simplified

Step-by-step explanation:

they are not the same term so there is no way to add them together

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3 years ago

if the interest earned was $55.20 on an investment of $230 that has a rate of 3%, how long was the money invested?

noname [10]

Answer:

8 years

Step-by-step explanation:

5 0

3 years ago

Okay dudes and dudets wanna help me out heres the problem

olga2289 [7]

$\bf \begin{array}{|c|c|l} \cline{1-2} \stackrel{\textit{years after 2000}}{x}&\stackrel{\textit{millions of volunteers}}{y}\\ \cline{1-2} 4&6.1\\ 10&11.1 \\ \cline{1-2} \end{array} \qquad \qquad (\stackrel{x_1}{4}~,~\stackrel{y_1}{6.1})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{11.1})$

$\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{11.1-6.1}{10-4}\implies \cfrac{5}{6} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6.1=\cfrac{5}{6}(x-4)\implies y-6.1=\cfrac{5}{6}x-\cfrac{10}{3} \\\\\\ y=\cfrac{5}{6}x-\cfrac{10}{3}+6.1\implies y=\cfrac{5}{6}x-\cfrac{10}{3}+\cfrac{61}{10}\implies \blacktriangleright y=\cfrac{5}{6}x+\cfrac{83}{30} \blacktriangleleft$

now, for 2009, that's 9 years after 2000 so x = 9, and 2014, well clearly x = 14, so

$\bf \stackrel{x = 9}{y=\cfrac{5}{6}(9)+\cfrac{83}{30}}\implies y=\cfrac{15}{2}+\cfrac{83}{30}\implies y=\cfrac{154}{15}\implies y=10\frac{4}{15} \\\\\\ \stackrel{x = 14}{y=\cfrac{5}{6}(14)+\cfrac{83}{30}}\implies y=\cfrac{35}{3}+\cfrac{83}{30}\implies y=\cfrac{433}{30}\implies y=14\frac{13}{30}$