Ask question

Ask question

All categories

3 years ago

10

I had finish to solve the problems from the sentences,but I got stuck when I barely realized that the cost of one daylily I got

is -2. I used this method by elimination.

1 answer:

Genrish500 [490]3 years ago

8 0

You lost minus when you were adding two equations.
-176= - 22x -12y
<span>144 = 6x +12y
</span>-32= - 16x
x=2

88=11x+6y,
88=11*2+6y
6y=66
y=11

Check:
88=11x+6y=11*2+6*11=88 True
144=6x+12y=6*2+12*11=12+132=144 True

The cost of daylilies is $2.
The cost of pot of ivy is $11.

You might be interested in

16 POINTS! NO LINKS! SHOW ALL WORK!

alexira [117]

Answer:

d

a

Step-by-step explanation:

f(3)= 3(3)-1

f(3)=9-1=8

f(x+1)= (x+1)^2-3(x+1)+2

=x^2+2x+1-3x-3+2

=x^2-x

8 0

3 years ago

Identify the vertex, the axis of symmetry and the y intercept of the parabola below.<br>please.

solmaris [256]

1,2 cause of the o and y axis

8 0

3 years ago

Read 2 more answers

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

4sinθ – 1 = - 3 for 0<θ< 360

EastWind [94]

Answer:

$\theta = 210^\circ$ or $\theta = 330^\circ$

Step-by-step explanation:

$4 \sin \theta - 1 = -3$

$4 \sin \theta = -2$

$\sin \theta = \dfrac{-2}{4}$

$\sin \theta = -0.5$

For sin θ = 0.5, the reference angle is θ = 30 deg.

$\sin 30^\circ = 0.5$

$\theta = 210^\circ$ or $\theta = 330^\circ$

7 0

3 years ago

Which cannot be used in a proof?

Gwar [14]

Hello,

you may not used what you are going to prove in a proof (la thèse)

4 0

3 years ago

Read 2 more answers