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vitfil [10]
2 years ago
15

i have 30 coins, all nickels, dimes and quarters, worth $4.60. there are two more dimes than quarters.. how many of each kind of

coin do i have?
Mathematics
1 answer:
Oliga [24]2 years ago
4 0

Answer:

Step-by-step explanation:

I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.

..

let quarters be x

dimes = x+2

...

dimes + quarters = x+x+2=2x+2

...

nickels = 30-(2x+2)

...

5(30-(2x+2))+10(x+2)+25x=460

5(30-2x-2)+10x+20+25x=460

150-10x-10+10x+20+25x=460

160+25x=460

-160

25x=460-160

25x=300

/25

x=300/25

x=12 ---- quarters

x+2= 12+2=14 dimes

30-(2x+2)=4 nickels

...

check

4*5+14*10+12*25=20+140+300=460

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