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guajiro [1.7K]
4 years ago
14

Andrea has a yard shaped like parallelogram ABCD. The garden area, parallelogram EFGB, has an area of 105 ft2004-05-02-04-00_fil

es/i0170000.jpg. If Andrea wants to sod the rest of her yard, how many square feet of sod should she order?
Mathematics
1 answer:
Lynna [10]4 years ago
5 0

The area of a parallelogram is simply calculated using the formula:

A = b * h

Where,

b = length of the base = 45 ft

h = height which is perpendicular to the base = 21 ft

Using the formula, we calculate the total area of the yard.

A = b* h

A = 45 ft * 21 ft

A = 945 ft^2

Now we don’t want to sod the Garden area for the most obvious reason. The garden has an Area of 105 ft^2, we subtract this to the total area giving us,

Area to sod = 945 ft^2 – 105ft^2

<span>Area to sod = 840 ft^2</span>

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Braxton opened up his checking account with $500. On Monday, he withdrew $120 to purchase a pair of shoes. On Wednesday, he depo
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The radius of the circle whose equation is (x-3)^2 + (y+1)^2 = 16 is
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4

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4 0
3 years ago
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7 0
3 years ago
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

16 = PM

PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

15 = PM

PM = 15 cm

3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

7 0
3 years ago
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