Take DEBC a parralelogram
Parralel sides are DE and BC
THEREFORE,
1/2*(a+b)*h
1/2*(6+15)*h
1/2*(21)*h=0
10.5*h=0
h=-10.5
Let us denote the smaller even integer by
.
Then, the next even integer must be
.
To verify, set
as any even number, say
.
Then, the next even integer must be 2 more than this number, i.e.
.
The sum of these two consecutive even integers can be expressed as:
We are told that this sum divided by four is 189.5, i.e.
Multiplying both sides by 4 will reverse the division:
Subtracting 2 from each side will reverse the addition:
Dividing both sides by 2 will reverse the multiplication:
Therefore, the two consecutive integers must be
378 and
380.
Check this:
Answer:idk
Step-by-step explanation:
idk
Answer:
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Step-by-step explanation:
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