The theorems that apply are A(HL) D(SAS) E(LL)
<h3>What are similar triangles?</h3>
Two triangles are said to be similar if their corresponding angles are equal and their corresponding lengths are in the same proportion.
Analysis:
The two triangles are similar according to the HL theorem since the hypotenuse of the two triangles are equal and one of the sides is same in both triangles. HL theorem applies.
The two triangles are similar according to LL theorem since the other lengths apart from the hypotenuse are also equal.
since two sides of both triangles are equal and there is an included angle 90 degree between the equal sides, the triangles are similar based on SAS.
Learn more about similar triangles: brainly.com/question/2644832
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<span>cos 2x + sqrt(2) sinx=1
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Note that: cos 2x = cos^2x - sin^2x = (1-sin^2x) - sin^2x = 1 - 2sin^2x.
So, when alternatively written, you have the following equation:
</span>- 2sin^2x + sqrt(2)sinx + 1 = 1
- 2sin^2x + sqrt(2)sinx = 0
Then, let z=sin(x). So you get,
- 2z^2 + sqrt(2)z = 0
z(- 2z + sqrt(2)) = 0
Either z=0, or - 2z + sqrt(2) = 0 ---> z=sqrt(2)/2.
Then, since z=0 or z=sqrt(2)/2, therefore sin(x)=0, or sin(x)=sqrt(2)/2.
Then, for you remains just to list the angles. (Let me know if this is not fair or if you got questions.)
The answer is A so pick that
Answer:gd
Step-by-step explanation:
Vygfy
