Question

Car A travels 20 mph faster than Car B. In the same time that Car A travels 208 mi, Car B travels 156 mi. Find their speeds. The speed of Car A is and the speed of Car B ​

Answer 1

Step-by-step explanation:

Assuming the speed of car B to be x and the speed of car A to be x+20

156 = 208

x. x+20

156(x+20)= 208x

156x+3120=208x

3120=208x-156x

3120=52x

x=60

The speed of car A is (x)= 60

The speed of car B is(x+20)= 80

Answer 2

Answer:

$\huge\colorbox{red}{Car\: A=80}\colorbox{blue}{Car B=60}$

Step-by-step explanation:

to understand this

you need to know about:

• equation
• PEMDAS

let's solve:

let the speed of car A be A

let the speed of car B be B

according to the first condition:

$\quad A=B+20$

according to the second condition:

$\quad 156(A)=208B$

1. $\text{substitute the value of A into the equation:}\\ \sf \implies 156(B+20)=208(B)$
2. $\sf distribute:\\ \implies 156B+3120=208B$
3. $\sf \: substract\: 156B \: from \: both \: sides : \\ \implies \: 156 B -156 B + 3120 = 208 B - 156 B \\ \implies \: 3120 = 52 B$
4. $\sf divide \: both \: sides \: by \: 52 : \\ \implies \frac{52B}{52} = \frac{3210}{52} \\ \therefore \: B = 60$

therefore

$\text{the speed of car A is 60+20=80}$