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maxonik [38]
3 years ago
9

Calculate the product 78.93 times 32.45

Mathematics
2 answers:
Alona [7]3 years ago
7 0

Answer:

2561.2785

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago
7 0

Answer:

<h2>2561.2785</h2>

Step-by-step explanation:

           7 8 9 3

×           3 2 4 5

+         3 9 4 6 5

+       3 1 5 7 2  

+     1 5 7 8 6    

+   2 3 6 7 9      

=  2 5 6 1 2 7 8 5

Hope this helps!!

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Nknjjhbvyugvtfituyjnjjjjjnnnnj
-Dominant- [34]

Answer:

indeed

Step-by-step explanation:

3 0
3 years ago
What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction? Take the square root of both
balu736 [363]

Answer:

The first step is

Take the square root of both sides of the equation

Step-by-step explanation:

we have

x^{2} =\frac{9}{16}

Solve for x

step 1

Take square root both sides

x=(+/-)\frac{3}{4}

the solutions are

x=+\frac{3}{4} and  x=-\frac{3}{4}

therefore

The first step is

Take the square root of both sides of the equation

5 0
3 years ago
Read 3 more answers
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
S(x)= 22x-8 and f(x)= -5. What is s(x) x f(x)?
zloy xaker [14]
-110x+40
You need to use the distributive property for this problem
You multiply 22x times -5 (which is -110x) and -8 times -5 (which is 40) to get -110x+40
6 0
3 years ago
Can someone help me asap!! am timed right now​
Aneli [31]

Answer:

Step-by-step explanation:

Find the value of the left hand side (LHS)

LHS = 1/4 // 5/6

LHS = 1/4 * 6/5

LHS = 6/20

LHS = 3/10

Now what will make 3/10 on the right?

B:  1/4  * 6/5 = 6/20 = 3/10

a = 4

b = 6

c = 5

7 0
3 years ago
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