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Dafna11 [192]
3 years ago
11

which measure of central tendancy is found by calculating the sum of all data in the set divided by the number of data values in

the set? median mean mode interquartile range
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
<span>The correct result to the question would be mean.

The mean (average) is found by calculating the sum of all data in the set divided by the number of data values in the set.
The median is the middle value in the list of data values.
The mode is the value which occurs most often.
</span><span>The interquartile range is the difference between the third and the first quartiles.</span>
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A researcher computes the following 2 x 3 between-subjects ANOVA, in which 11 participants were observed in each group. Which ef
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Answer:

D. There were no significant effects.

Step-by-step explanation:

The table below shows the representation of the significance level using the two-way between subjects ANOVA.

Source of Variation            SS          df          MS          F                P-value

Factor A                             10          1              10           0.21           0.660

Factor B                             50         2             25          0.52          0.6235  

     

A × B                                  40          2             20         0.42           0.6783

Error                                   240        5             48           -               -

Total                                   340       10             -             -                  -

From the table above , the SS(B) is determined as follows:

SS(B) = SS(Total)-SS(Error-(A×B)-A)

         =  340-(240-40-10)

         = 50

A researcher computes the following 2 x 3 between-subjects ANOVA;

k=2

n=3

N(total) = no of participants observed in each group =11

df for Factor A= (k-1)

=(2-1)

=1

df for Factor B = (n-1)

=(3-1)

=2

df for A × B    

 = 2 × 1

 = 2

df  factor for total

=(N-1)

=11-1

=10

MS = SS/df

Thus, from the table, the P-Value for all data is greater than 0.05, therefore we fail to reject H₀.

4 0
2 years ago
Complete the solution of the equation. Find the value of y when x equals -3. 2x-5y =-21
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The answer is y=3 ....

5 0
3 years ago
Sixty percent (60%) of those who attended the soccer game were parents. There were 120 people who
IrinaVladis [17]

Answer:

72

Step-by-step explanation:

<u>Given:</u>

There were 120 people in total.

60% were parents.

<u>To find:</u>

Number of parents attended.

Solution:

1. 60% of 120

It can also be written as:

\frac{60}{100}\times \frac{120}{1}

Simplify

  • Cancel zeros

\frac{60}{100}\\\\=\frac{6}{10}

  • Divide by common factor (2)

\frac{6\div2}{10\div2}=\frac{3}{5}

2. \bold{\frac{3}{5}\times \frac{120}{1}}

Multiply

\frac{3\times120}{5\times1} = \frac{360}{5}

Divide

\frac{360}{5}= 360\div5=72

Therefore, 72 parents attended the game.

4 0
2 years ago
State all integer values of x in the interval [0,7] that satisfy the following inequality
Anestetic [448]

Answer:

x>3/2

Step-by-step explanation:

3 0
3 years ago
A need help Dilations-He Said, She Said (12/10)
Elodia [21]

Answer:

We conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

Step-by-step explanation:

Checking the location of the vertices of the original triangle ΔDEF

  • D(-2, 4)
  • E(2, 4)
  • F(0, 2)

Checking the location of the dilated vertices of the image triangle ΔD'E'F'

  • D'(-5, 10)
  • E'(5, 10)
  • F'(0, 5)

Notice that if we multiply the vertices of the original triangle ΔDEF by 5/2, we get the correct image vertices of image triangleΔD'E'F'

i.e.

D(-2, 4) → D'(5/2 (-2), 5/2 (4))  → D'(-5, 10)

E(2, 4) → E'(5/2 (2), 5/2(4))  → D'(5, 10)

F(0, 2) → E'(5/2 (0), 5/2(2))  → F'(0, 5)

Thus, we conclude that the original triangle ΔDEF is dilated by a scale factor of 5/2 to get the image triangle ΔD'E'F'.

Therefore, 'Cárl' is correct. Hence, option 'a' is correct.

6 0
2 years ago
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