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Mashcka [7]
3 years ago
8

Can anyone help me with this problem?3a=9a^2-30​

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
7 0

Answer:

X1 = 2 X= -\frac{5}{3}

Step-by-step explanation:

You must pass the 3 a to the other side in negative and use the quadratic formula

Roman55 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

X1 = 2 X= -\frac{5}{3}

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Need help ASAP answer ASAP
Feliz [49]

Answer:

1A= 27+43= 70

Step-by-step explanation:

you add the values of each thing they are asking so for the next one you would do, Cakes Plus Biscuits. So 86+59 and that will give you your answer for 1B

6 0
3 years ago
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals​ surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                              P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of individuals who work at home at least once per week = \frac{41}{250} = 0.164

           n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                             level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<em>99% confidence interval for p</em> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } , 0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } ]

 = [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0
3 years ago
Please help i need this done soon!!
frosja888 [35]

Answer:

f(2) = -2

Step-by-step explanation:

plug in 2 to wherever x is in this statement:

f(2) = -2(2^2) - 2(2) + 10

f(2) = -2(4) - 4 + 10

f(2) = -8 - 4 + 10

f(2) = -2

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3 years ago
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An entomologist is studying the reproduction of ants. If an ant colony started with 50 ants, and each day, their population incr
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Step-by-step explanation: Ants are one of the most abundant insects on our planet and the reasons are their eusocial, complex societal behaviors and their ability to survive in many and various ecosystems. Like most other animal societies, reproduction is one of the core reasons why ants are so prevalent.

Acrobat Ant

Reproduction for ants is a complex phenomenon that involves finding, selecting and successfully fertilizing females to ensure that the eggs laid are able to survive and molt through the successive stages of the ant’s life cycle – larvae, pupae and adults.

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3 years ago
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What is the area of the triangle shown below?
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Answer:

300 mm squared

Step-by-step explanation:

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3 years ago
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