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Firdavs [7]
3 years ago
15

Stacy is measuring milk to make pancake batter. The recipe calls for \dfrac{3}{4} 4 3 ​ start fraction, 3, divided by, 4, end fr

action of a jug of milk. She has \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, end fraction of a jug now. How much more milk does she need?
Mathematics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

1/2 cup of milk

Step-by-step explanation:

Given

Total cup of milk needed = 3/4 cup of milk

Amount she has = 1/4 cup of milk

The amount of milk she needed = Total - Amount she has

Amount she needed = 3/4 - 1/4

Amount she needed = (3-1)/4

Amount she needed = 2/4

Amount she needed = 1/2

Hence she needs 1/2 cup of milk more

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Abdul rolls a fair six-sided die and a fair four-sided die simultaneously. The sample space of all possible
gregori [183]

Answer: 7/24

Step-by-step explanation:

Probability is the branch of mathematics that is concerned with the numerical descriptions of how likely an event will occur or how likely a proposition is true

The probability that the six-sided die is three or Abdul rolls doubles is 7/24. The calculation is attached.

4 0
3 years ago
I’m not very good at these so someone help me out :,)
Lilit [14]

Answer:

-4,-1

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6 0
3 years ago
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The function h is a quadratic function whose graph is a translation 3 units left and 4 units up of the parent
jeka57 [31]

Answer:

D ( if you add +4 to the (x + 3)^2)

Step-by-step explanation:

Parent function is f(x) = x^2

A translation 3 units left gives y = )x + 3)^2

- and 4 up gives y = (x + 3)^2 + 4 - vertex form.

Standard form :

y = x^2 + 6x + 9 + 4

= x^2 + 6x + 13.

4 0
2 years ago
What is the value of the expression 3^2(2^3+4)/2^2?
Step2247 [10]

Answer:

27

Step-by-step explanation:

7 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
2 years ago
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