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Semmy [17]
3 years ago
13

PLEASE ANSWER ASAP. How are direct democracy and representative democracy similar?

Mathematics
1 answer:
HACTEHA [7]3 years ago
5 0
They are sim because there just are short bud I don’t know
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Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth
never [62]

Answer:

The data does not provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds.

Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level.

Step-by-step explanation:

Null hypothesis (H0): mu = 8.2 seconds

Alternate hypothesis (Ha): mu < 8.2 seconds

Significance level = 0.04

p-value = 0.0401

Using the p-value approach for testing hypothesis, do not reject H0 because the p-value 0.0401 is greater than the significance level 0.04.

There is not sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds.

7 0
3 years ago
An Amazing Graph please answer it
dlinn [17]
No clue
what you are trying to show us

8 0
4 years ago
Statement: If 3x = 6, then x = 2. What is the contrapositive of the statement? Emeans not equal​
nikitadnepr [17]

Answer:

x=2

Step-by-step explanation:

you are correct for x=2 because 6 divided by 3 is 2

5 0
3 years ago
Linda has to buy stickers, erasers, and a pencil. She can only spend $3. A sticker costs $0.35, an eraser costs $0.99, and a pen
Hitman42 [59]
No. The total will be $3.62
4 0
3 years ago
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
4 years ago
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