Answer:
i. 10210212
ii. 100 101 001 in BASE 2
iii. 46.4631
iv. 12.453125
Explanation:
i. Converting to base 10 we get
= 10 x 162 + 13 x 161 + 9 x 160 = 2777
Converting to base 10 we get =
2777/3 = 925 with remainder 2
925/3 = 308 with remainder 1
308/3 = 102 with remainder 2
102/3 = 34 with remainder 0
34/3 = 11 with remainder 1
11/3 = 3 with remainder 2
3/3 = 1 with remainder 0
1/3 = 0 with remainder 1
Hence the Answer is 10210212
ii. = Octal is taken in pair of 3 bits , Writing binary of each number in 3 bits we get = 100 101 001 in BASE 2
iii. = 1 x 52 + 2 x 51 + 3 x 50 + 3 x 5-1 = 38.6 in decimal
Converting to Octal we get
38 /8 = 4 with remainder 6
4 /8 = 0 with remainder 4
.6 x 8 = 4.8
.8 x 8 = 6.4
46.4631
iv. = 1x 81 + 4 x 80 + 3 x 8-1 + 5 x 8-2 = 12.453125
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Answer:
The answer is "Pass the cable into the ceiling instead of over the floor".
Explanation:
Network access explains the complex process of link different parts of the network with each other, e.g. while using switches, routers, and access points, and whether, that system works.
- To replace the cable with a pair cable graded in plenum, covered, twisted.
- We use the cable to pass through the ceiling rather than through the concrete, eliminating the issue and stopping it from occurring again.
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
class Window //defining a class Window
{
private:
int width, height;//defining integer variable
public:
friend ostream& operator << (ostream& stm, Window& width)//defining a friend function that takes two parameters
{
return stm<<"a ("<<width.width<<" x "<<width.height<<") window"; //use return keyword that return its values
}
Window(int width, int height): width(width), height(height)//defining parameterized constructor that inherit width and height in its parameters
{}
};
int main() //Main method
{
Window w(80,90);//calling class constructor
cout<<w;//print object value
return 0;
}
Output:
a (80 x 90) window
Explanation:
In the above code, a class "Window" is defined that uses a friend function "ostream& operator" is declared that uses the "ostrea&" as a data type to hold two-variable "stm and w" in its parameter, and declared the parameterized constructor to hold value by inheriting width and height in its parameters.
Inside the main method, a class object is created that calls the constructor and uses the print method to print object value.
Answer: It's similiar to the quote "You bring out the best of me" When you're in love, you feel the need to be yourself and that you don't have to hide it. Love brings out the real you.
Hope this helps.
Explanation: