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IgorC [24]
3 years ago
10

Given the strings s1 and s2 that are of the same length, create a new string consisting of the last character of s1 followed by

the last character of s2, followed by the second to last character of s1, followed by the second to last character of s2, and so on (in other words the new string should consist of alternating characters of the reverse of s1 and s2). For example, if s1 contained hello" and s2 contained "world", then the new string should contain "odlllreohw". Assign the new string to the variable s3.
Computers and Technology
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer:

See the code snippet in the explanation section

Explanation:

import java.util.Scanner;

public class Question {

   public static void main(String args[]) {

              Scanner scan = new Scanner(System.in);

 System.out.println("Enter first string: ");

 String s1 = scan.nextLine();

 System.out.println("Enter second string: ");

 String s2 = scan.nextLine();

 concatenateString(s1, s2);

 }

 

 public static void concatenateString(String firstString, String secondString){

 int stringLength = firstString.length() - 1;

 String s3 = "";

  if (firstString.length() != secondString.length()){

  System.out.println("String do not have equal length");

 } else {

  for(int i = stringLength; i >= 0; i--){

   s3 += String.valueOf(firstString.charAt(i)).concat(String.valueOf(secondString.charAt(i)));

  }  

  System.out.println(s3);

 }

   }

}

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void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

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{

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C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

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printf("3 Subsets are\n");

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for(int j =i+1; j < n ; j++)

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int main()

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cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

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