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Vlad [161]
3 years ago
6

the length of a rectangle is 3cm more than the width. find the length and the width if the perimeter of the rectangle is 98cm.

Mathematics
1 answer:
laila [671]3 years ago
7 0

The perimeter of a rectangle is <u>length + length + width + width</u>.

We know that the length of a rectangle is 3cm more than its width, which gives us the equation:  (l for length and w for width)

l = 3 + w

We also know that the perimeter of the rectangle is 98cm, which gives us the equation:

98 = 2l + 2w         (equation for perimeter of a rectangle as noted above)

We can divide both sides of this equation by 2 to get:

49 = l + w

Now we'll stick l = 3 + w into the above equation, which gives us:

49 = 3 + w + w

which simplifies to 49 = 3 + 2w.

Now we'll subtract 3 from both sides:

49 - 3 = 46

3 + 2w - 3 = 2w

which gives us 46 = 2w.

Dividing both sides by 2 gives us 23 = w.

Substituting w = 23 into the equation l = 3 + w gives us:

l = 3 + 23

l = 26cm.

Let's check our answer.  26cm is 3cm more than 23cm.  26cm + 26cm + 23cm + 23cm gives us 98cm.  The length is 26cm and the width is 23cm.


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Answer:

The width is 5.25 feets

Step-by-step explanation:

The dimensions of the two rectangular wooden boards that Elenor and Max used to make a set for the school play are shown in the attached photo. The widths of the two boards are equal. The lengths are 6 feets and 51/2 feets

Area of each rectangular length, L × Width, W

Area of the longer rectangular board

= 6x W = 6W feet^2

Area of the shorter rectangular board

= 11/2 x W = 11W/2 feet^2

The area of the set is 60-3/8 square feet. This is equal to 483/8 feet^2.

Therefore,

483/8 = 6W + 11W/2 = 23W/2

8 × 23W = 483 × 2

184W = 966

W = 966/184 = 5.25 feets

3 0
3 years ago
Which of the following are considered measures of center? I. mean II. median III. interquartile range A. III only B. I and II on
andrezito [222]
Answer: Choice B) I and II only

The mean and median are considered measures of center as they represent the average of a data set. The average basically being a point that collectively speaks for all of the data. For example, if you have a group of basketball players whose heights range from 5'11" to 6'9", then there is no single height to report; however, we can compute the average to get a basic idea of the single height. The interquartile range (IQR) is a measure of variability or spread of the data. The higher the IQR, the more spread out the data is. Recall that 50% of the data is represented by the IQR and that IQR = Q3 - Q1 where Q1 and Q3 are the first and third quartiles respectively. So because the IQR is a measure of spread, it is not considered a center point.
4 0
3 years ago
What is the solution set of {xlx&lt;-3}{xlx&gt;5)?
Anna007 [38]
<h3>Answer: C. Empty set</h3>

Explanation:

The first set {x | x < -3} means we're talking about numbers smaller than -3. This includes -4, -5, -6, etc

The second set {x | x > 5} means we're talking about numbers larger than 5. So things like 6,7,8,...

Combining both at the same time, we want to find a number that is both smaller than -3 and larger than 5. This is impossible as no such number exists. You can pick one or the other, but not both.

There are no solutions. Since there are no solutions, the solution set is the empty set.

8 0
3 years ago
Help, I need it fast! D:
patriot [66]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish the simple interest formula which we will require to solve this problem as displayed below:

Simple Interest = Principal × Rate of Interest × No. of Time Periods

I = PRN

Now let's substitute the values from the problem into this formula as displayed below:

I = $90

P = ?

R = 6%

N = 3 years

I = PRN

90 = P × 0.06 × 3

P = 90 / 0.06 × 3

P = 90 / 0.18

P = $500

ANSWER:

As the principal and the amount borrowed is the same, Claire borrowed $500. Therefore, the answer is:

D ) $500

Please mark as brainliest if you found this helpful! :)
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Answer:

Step-by-step explanation:

Total number of rolls = 50

Number of times rolling a 6 = 8 times

Number of times not rolling a 6 = 50 -8 = 42

P(~6) = 42/50 = 0.84

8 0
2 years ago
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