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umka21 [38]
2 years ago
8

Jordan performed an experiment using a number cube. He rolled a number cube 50 times. He found that he rolled a 6 a total of 8 t

imes. What is the experimental probability that he did not roll a 6?
Mathematics
1 answer:
bazaltina [42]2 years ago
8 0

Answer:

Step-by-step explanation:

Total number of rolls = 50

Number of times rolling a 6 = 8 times

Number of times not rolling a 6 = 50 -8 = 42

P(~6) = 42/50 = 0.84

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I got 480 square feet. I assume that the apartment was a rectangle so the sides were 3in by 5in. Then I converted inches to feet and then found the area again
3 0
3 years ago
What is the value of the expression below when z<br> 8 and w<br> 3?<br> 9z-8w
Gnesinka [82]

Answer:

48

Step-by-step explanation:

1) 9*8=72

2) 8*3=24

3)72-24=48

5 0
3 years ago
Abby, Bik, Cari, Dawn, and Ellen collect T-shirts. Abby has the most. Bik has 2.5 times as many T-shirts as Cari. Dawn has 1/3 a
bixtya [17]
A=abby's shirts
b=bik's shirts
c=cari's shirts
d=dawn's shirts
e=ellen's shirts


a> everybody
b=2.5c
d=(1/3)c
a+b+c+d=120
e=2d+1
e=13
oook

e=13=2d+1
13=2d+1
12=2d
d=6

d=(1/3)c
6=(1/3)c
18=c

b=2.5c
b=2.5(18)
b=45

a+b+c+d=120
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4 0
3 years ago
36 red beads, 49 green and 76 blue beads are to be packed into packets, each containing 3 red, 5 green and 7 blue beads respecti
lakkis [162]
9 packets.

36 divided by 3 = 12
49 divided by 5 = 9.8
76 divided by 7 = 10.8

Maximum packets that can be obtained is 9 packets because only 9 packets with 5 green beads each can be packaged.
6 0
3 years ago
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
Klio2033 [76]
The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6



The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12


The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48

Answer: 
D.  -6,12,48
6 0
3 years ago
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