Elenor and Max used two rectangular wooden boards to make a set for the school play. One board was 6 feet long, and the other wa
s 5-1/2 feel long. The two boards has equal widths. The total area of the set was 60-3/8 square feet. What was the width?
1 answer:
Answer:
The width is 5.25 feets
Step-by-step explanation:
The dimensions of the two rectangular wooden boards that Elenor and Max used to make a set for the school play are shown in the attached photo. The widths of the two boards are equal. The lengths are 6 feets and 51/2 feets
Area of each rectangular length, L × Width, W
Area of the longer rectangular board
= 6x W = 6W feet^2
Area of the shorter rectangular board
= 11/2 x W = 11W/2 feet^2
The area of the set is 60-3/8 square feet. This is equal to 483/8 feet^2.
Therefore,
483/8 = 6W + 11W/2 = 23W/2
8 × 23W = 483 × 2
184W = 966
W = 966/184 = 5.25 feets
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This question likely should be done before the other one. What you are trying to do is give C a value. So you need to remember that C is always part of an indefinite integral.
y =
y = sin(x) - cos(x) + C
y(π) = sin(π) - cos(π) + C = 0
y(π) = 0 -(-1) + C = 0
y(π) = 1 + C = 0
C = - 1
y = sin(x) - cos(x) - 1 <<<<< Answer
Problem Two
Remember that
y( - e^3 ) = ln(|x|) + C = 0
y(-e^3) = ln(|-e^3|) + C = 0
y(-e^3) = 3 + C = 0
3 + C = 0
C = - 3
y = ln(|x|) - 3 <<<< Answer