For the given quadratic equation we only have a maximum at y = 18.
<h3>
How to find the extrema of the given function?</h3>
Here we have:
Notice that this is a quadratic equation of negative leading coefficient.
Then we have a maximum at the vertex, and both arms tend to negative infinity as x tends to infinity or negative infinity.
The vertex is at:
x = -(-4)/(2*(-2)) = -1
The maximum is:
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The 50th term in the sequence is 199
Arithmetic sequence
The nth term of an arithmetic sequence is expressed as:
Tn = a+ (n - 1)d
where:
- a is the first term
- n is the number of terms
- d is the common difference
The sequence formed by the amount of Whatchamacallits produced as;
3, 7, 11, 15...
a = 3
d = 11-7 = 7-3 = 4
Substitute
Tn = 3 + (n-1) * 4
Tn = 3 + 4n -4
Tn = 4n - 1
Hence the explicit formula that models the production for the nth term of the sequence is Tn = 4n - 1
If n = 50
T50 = 4(50) - 1
T50 = 199
Hence the 50th term in the sequence is 199
Learn more on sequence here; brainly.com/question/6561461
Answer:
28
Step-by-step explanation:
The value with maximum frequency is mode.
so here 28 is mode because it is repeates maximum number of times.
Answer:
Step-by-step explanation:
x + 3y = 1
-3x - 3y = -15
-2x = -14
x = 7
7 + 3y = 1
3y = -6
y = -2
(7, -2)