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Inessa [10]
3 years ago
8

Best Buy wants to know if frequent customers prefer Sony or Fuji cameras. They asked everyone at the sandwich shop next door wha

t kind of camera they prefer. This sampling method representative of the entire Rewards customers.
Mathematics
2 answers:
otez555 [7]3 years ago
4 0
This senecio is in reliable because how do you know if the people at the sand which shop next door are frequant customers
Katena32 [7]3 years ago
3 0

Answer:

This sampling method is not representative of the entire Rewards customers.

Step-by-step explanation:

To know if frequent customers prefer Sony or Fuji cameras, you have to sample within the frequent customers' population. People from the sandwich shop next door are not necessarily frequent customers in Best Buy.

I would send a questionary to all frequent customers through email with the question "What branch of cameras do you prefer?" Or if is only between Sony of Fuji, then the question would be "What branch of cameras do you prefer, Sony or Fuji?" Not all frequent customers will answer, but you will get better representativeness of the frequent customers' population.

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a car travelling at an average speed of 100 km/h covers a certain distance in 3 hours. at what average speed must the car travel
Furkat [3]

Answer:

Needs to have an average speed of 150km/h

Step-by-step explanation:

With the current average of 100 km/h in a 3-hour span, you would cover 300km. Since you want to cover that same amount (300km) in 2 hours all you do is 300/2 which is 150. Meaning you need an average speed of 150 km/h

7 0
2 years ago
Make 29 in three different ways
Kazeer [188]

20 + 9

14.5 • 2

58 ÷ 2

4 0
4 years ago
In a certain Algebra 2 class of 26 students, 10 of them play basketball and 5 of them
Paladinen [302]

K=basketball, S= baseball

10K

5S

3 K & S

26 total

P(K) = 10/26, P(S) = 5/26 P(K^S) = 3/26

P(K v S) = P(K) + P(S) - P(K^S) = 10/26 + 5/26 - 3/26 = 12/26 = 6/13

Probability of randomly getting a student who plays either basketball or baseball = 6/13

7 0
2 years ago
Suppose that a population grows according to a logistic model with carrying capacity 6000 and k=0.0015 per year.. Write a logist
makvit [3.9K]
♥ thus y’/(yf-y) = k, where yf=6000; 
<span>♠ hence ln(yf-y) =-kx +C; </span>
<span>at x=0 y(0)=y0=1000, hence C= ln(yf-y0); </span>
<span>and we get: </span>
<span>ln((yf-y)/(yf-y0) =-kx; or; </span>
<span>yf-y =(yf-y0)*exp(-kx); at last </span>
<span>♦ y = 6000- 5100*exp(-0.0015*x); 
</span>
<span><span><span>dy</span><span>dt</span></span>∝y=ky</span>separate the variables<span><span><span>dy</span>y</span>=kdt</span>integrate both sides:<span>lny=kt+C</span><span>y(t)=C<span>e<span>kt</span></span></span>by plugging in t=0 we find that C the original population<span>y(0)=C<span>e0</span>=C⟹C=<span>y0</span></span>so we get<span><span>y=<span>y0</span><span>e<span>kt</span></span></span></span>
5 0
4 years ago
(please pleaseee help. I screenshot the question and choices )
inna [77]
The answer is yes, 1:1,4
6 0
3 years ago
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