Answer:
def newton(n):
#Define the variables.
t = 0.000001
esti = 1.0
#Calculate the square root
#using newton method.
while True:
esti = (esti + n / esti) / 2
dif = abs(n - esti ** 2)
if dif <= t:
break
#Return the result.
return esti
#Define the main function.
def main():
#Continue until user press enters.
while True:
try:
#Prompt the user for input.
n = int(input("Enter a number (Press Enter to stop):"))
#display the results.
print("newton = %0.15f" % newton(n))
except:
return
#Call the main function.
main()
Answer:
# Python program to shuffle a deck of card
# importing modules
import itertools, random
# make a deck of cards
deck = list(itertools.product(range(1,14),['Spade','Heart','Diamond','Club']))
# shuffle the cards
random.shuffle(deck)
# draw five cards
print("You got:")
for i in range(5):
print(deck[i][0], "of", deck[i][1])
Output
You got:
5 of Heart
1 of Heart
8 of Spade
12 of Spade
4 of Spade
Explanation:
Answer:
You need to explain the entire network layout first.
Explanation:
Bringing on new IT Staff can be time consuming. But depending on the possession you need to explain to them how the domain lay out is.
Answer:
1.) Write the formula, which assigns double x to double n raised to the double z power.
Answer: 2\times x → 2\times n^(2\times z<u>)</u>
2.) Write a formula, which will add 5 to the cube of double t times double n, and assign it to double x.
Answer: 5\plus 2\times t^3→2\times x
3.) Write a formula, which will assign double x to square root of the sum of the squares of the lengths of the two legs of a triangle. Declare double leg1, and double leg2, in order to find the hypotenuse. (Pythagorean Theorem)
Answer: 2\times x → \sqrt \{(l^2)_1 + (l^2)_2\}= hypotenuse
4.) Write a program that find the distance between two values on the number line by taking the absolute value of their difference. Assign the answer to double x. The two numbers have been declared as follows:
double num1, num2
Answer: length = \sqrt\{|num2 - num1\|} → 2\times x
Explanation:
