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BlackZzzverrR [31]
2 years ago
11

Convert the following binary to decimal number . a). 101101 ​

Computers and Technology
2 answers:
KonstantinChe [14]2 years ago
5 0
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above

32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
adoni [48]2 years ago
3 0

(101101)_2\\\\=1\times 2^5 +  0 \times 2^4 + 1 \times 2^3 +1 \times 2^2 + 0 \times 2^1+1 \times 2^0\\\\=32+0+8+4+0+1\\\\=(45)_{10}

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Answer:

from random import randint

winner  = False

number = str(randint(10000, 99999))

while (not winner):

   correct = 0

   total = 0

   guess = input()

   

   if(number==guess):

       winner = True

   else:

       for i in range(5):

           if(number[i] == guess[i]):

               correct+=1

               total+=int(number[i])

       

       print('Correct: '+ str(correct))

       print('Total: '+ str(total))

print('Winner')

Explanation:

I´m gonna show a solution in python 3

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from random import randint

Step 2 create necesary variables to get the number and if the player is winner or not

winner  = False

number = str(randint(10000, 99999))

Step 3 loop while the player is not the winner

while (not winner):

Step 4 get the player guess number

guess = input()

Step 5 validate if the player win

if(number==guess):

       winner = True

Step 6 if the player is not winner review what numbers are  in the correct position

for i in range(5):

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               total+=int(number[i])

Step 7 print the hint

print('Correct: '+ str(correct))

print('Total: '+ str(total))

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