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BlackZzzverrR [31]
2 years ago
11

Convert the following binary to decimal number . a). 101101 ​

Computers and Technology
2 answers:
KonstantinChe [14]2 years ago
5 0
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above

32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
adoni [48]2 years ago
3 0

(101101)_2\\\\=1\times 2^5 +  0 \times 2^4 + 1 \times 2^3 +1 \times 2^2 + 0 \times 2^1+1 \times 2^0\\\\=32+0+8+4+0+1\\\\=(45)_{10}

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#section 1

def maxTemp(filename):

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   f.exists()

   if f.exists():

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#section 2

       next(f)

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       for i in range(len(res)-1):

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               maxdata = res[i]

       

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 #section 3  

       li = []  

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           li.append(line)

   

       

       a.close()

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#section 1:

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#section 2:

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