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BlackZzzverrR [31]
2 years ago
11

Convert the following binary to decimal number . a). 101101 ​

Computers and Technology
2 answers:
KonstantinChe [14]2 years ago
5 0
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above

32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
adoni [48]2 years ago
3 0

(101101)_2\\\\=1\times 2^5 +  0 \times 2^4 + 1 \times 2^3 +1 \times 2^2 + 0 \times 2^1+1 \times 2^0\\\\=32+0+8+4+0+1\\\\=(45)_{10}

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Write a program that asks a user to enter a date in month day year format (for example 10 12 2016) and displays the day of the w
AleksAgata [21]

Answer and Explanation:

Using javascript:

function dayof_theweek(){

var TodayDate = window. prompt("enter today's date in the format 'year, month, day' ");

var Datenow=new date(TodayDate);

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var Days=["monday","Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];

if(Dayofweek==indexOf(Days[Dayofweek]))

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}

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The program above uses a date object which uses the method getday to get the day of the week(get day returns an integer from 0 to 6).we then use a comparison operator == to test the condition that returned value Dayoftheweek is same with the index of the array Days and then print to a html document. The program may need improvements such as the fact that errors may arise when proper input isn't given, and therefore must be handled.

8 0
3 years ago
When storing used oil, it needs to be kept in ___________ containers.
tester [92]

Answer:

Plastic container

Explanation:

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5 0
3 years ago
A. Calculate the diffusion coefficient for magnesium in aluminum at 450°C.
SIZIF [17.4K]

Answer:

a) D = 4.88 * 10^(-14) m^2 / s

b)   <em>t </em>= 1.1 hr

Solution:

a) Magnesium in Aluminum diffusion:

D = Do * exp(-Qd / RT)

  =  (1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15)

  = 4.88 * 10^(-14) m^2 / s

D = 4.88 * 10^(-14) m^2 / s

b) The composition remains same at say the distance Xo:

(Cx - Co) / (Cs - Co) = Constant

Xo^2 / D_{550} * <em>t </em>= Xo^2 / D_{450} * 15

D_{550} * <em>t </em>= D_{450} * 15

(1.2 * 10^(-4) m^2 / s) * exp ( - 130,000 / 8.31 * 723.15) * <em>t</em>

(4.88 * 10^(-14) m^2 / s) * 15

by, solving for <em>t </em>we get:

 <em>t </em>= 1.1 hr

So, the time required is 1.1 hr.

5 0
3 years ago
Write the class RoadSegmet. The class inherits from Transportation Class. The Class have a vector hourlySpeeds data field which
OLEGan [10]

Answer:

The length of time on the road segment is calculated by taking it's distance and dividing by the speed at the time of departure. This length of time is then added to the departureTime parameter to get the arrivalTime.

Define a RiverSegment class that inherits from the base TransportationClass from above. This class will have a vector<double> scheduledDepartureTimes data field that will keep track of the departure time (e.g. 10.5 represents the time 10:30) of all ferries on the river. You can assume these are sorted. Additionally, there is a _speed value that is the speed of the ferry at all times (ferries tend to be consistently slow). There is a setSpeed function to change the _speed value. Additionally, there is an addDepartureTime(double hour) function to add a departure time to the vector. Make sure the time are sorted

Computing the arrival time for the RiverSegment is a little more complicated since you need to wait for the next available departure time. Once you find the next available departure time (after the departure time passed in), you need to add the length of time on the river segment. This is done by dividing the _distance by the _speed. Add the time on the river to the departure time (from the vector of departure times) and this will give you the arrive time.

note: If there is no departure time scheduled for after your planned departure, you need to take the first available departure the following day. Our solution assumes the departure times are the same every day.

TransportationLink.h

#include <string>

using namespace std;

#ifndef __TRANSPORTATIONLINK_H__

#define __TRANSPORTATIONLINK_H__

const int HOURS_PER_DAY = 24;

const int MINS_PER_HOUR = 60;

const int MINS_PER_DAY = MINS_PER_HOUR * HOURS_PER_DAY; //24 * 60

class TransportationLink {

protected:

string _name;

double _distance;

public:

TransportationLink(const string &, double);

const string & getName() const;

double getDistance() const;

void setDistance(double);

// Passes in the departure time (as minute) and returns arrival time (as minute)

// For example:

// 8 am will be passed in as 480 (8 * 60)

// 2:30 pm will be passed in as 870 (14.5 * 60)

virtual unsigned computeArrivalTime(unsigned minute) const = 0;

};

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3 years ago
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s2008m [1.1K]

Answer:

Network.

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I. Application layer.

II. Transport layer.

III. Internet layer.

IV. Network layer.

The network layer in the Transmission Control Protocol/Internet Protocol (TCP/IP) model is responsible for delivering data between two nodes.

Basically, this layer known as network layer is the fourth layer of the Transmission Control Protocol/Internet Protocol (TCP/IP) model and it is typically responsible for the transmission of packets from one network device to another.

4 0
3 years ago
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