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2 years ago

Geometry help greatly needed, check photo for more information! <3

Mathematics

1 answer:

vlabodo [156]2 years ago

8 0

Answer:

$\huge\boxed{\sf x = 55\°}$

Step-by-step explanation:

When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.

Here,

∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)

Given that: ∠DCB = 135° and ∠DAB = x

135 + x = 180

Subtract 135 to both sides

x = 180 - 135

x = 55°

$\rule[225]{225}{2}$

Hope this helped!

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Step-by-step explanation:

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Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

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First find the domain of both functions. Radicand can not be negative.

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$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

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So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

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3 years ago

write the slope - intercept equation of the line that passes through the point (6, "-1)" and has a slope of "-1/3"

TEA [102]

Answer:

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Step-by-step explanation:

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2 years ago