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andre [41]
3 years ago
15

Identify forces between two objects which are inversely proportional to the square of the distance between them. i. nuclear forc

e between two neutrons; ii. gravitation force btween two celestial bodies; iii. electrostatic force between two electrons. 1. i and ii only 2. ii only 3. none is true. 4. iii only 5. i only 6. all are true. 7. i and iii only 8. ii and iii only
Physics
1 answer:
nikdorinn [45]3 years ago
3 0
The force between two celestial bodies is a Newtonian gravitational force. 
It is also called Newton's law of universal gravitation. We can write it down mathematically in the following way:
F=G \frac{ m_{1} m_{2} }{ r^{2}}
We can see from this formula that gravitational force is <span>inversely proportional to the square of the distance between bodies.
The electrostatic force between two charges is Coulombs force. We can write it down like this: 
</span>F= k_{e} \frac{ q_{1} q_{2} }{ r^{2}}
This force is also inversely proportional to the square of the distance between interacting particles.
The nuclear force is a little bit more complicated. It can be expressed using the so-called Yukawa potential, which has the following form:
V_{y} =- g^{2} \frac{ e^{-ur} }{r}
This interaction does not follow the inverse-square law.
The final answer should be 8.
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An object is in circular motion how will the object behave if the centripetal force is removed
Monica [59]

If the force is removed, then there are no other forces acting on the object, the object will continue to move at constant velocity, meaning that it would move in a line tangent to the circular path.

8 0
4 years ago
How you do this resistor in circuit question?
lawyer [7]
If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series,  R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel,  R = (R1*R2)/(R1+R2)

1.)    60 is parallel with 40 and both are then in series with 20.

60//40   = (60*40)/(60+40) = 2400/100 = 24 

Now the 24 is in series with the 20 

R = 24 + 20 = 44 ohms.

2.)    80 is in series with 40 and both are then in parallel with 40.

Solving the series,  R = 80 + 40 =120.

Parallel:   120//40  =     (120*40)/(120+40) =  4800/160 = 30 
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel  =  (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel  =  (50*50)/(50+50)  = 2500/100   = 25.

Solving the series  = 50 + 25 =75 ohms.

Cheers.
3 0
4 years ago
Sitting at the top of a steep hill on a roller coaster (not moving), is an example of:
Marianna [84]
It’s an example of gravitational potential energy
3 0
3 years ago
Read 2 more answers
If the plates are pulled twice as far apart, but are kept connected to the battery, the electric field between the plates will b
never [62]

Electric field between two parallel plates will be halved as it was before.

What is the electric field between two plates:

The electric field lines of two parallel plates can be represented by straight lines perpendicular to both plates surfaces while carrying arrows that point from +Q plate A toward -Q plate B.

we know that,

The electric field between plates:

E=V / d

where,

V is battery voltage

d is separation distance between plates.

now If the plates are pulled twice as far apart, but are kept connected to the battery,

the separation distance becomes,

d' = 2d

so the new electric field will be:

E' = V / d'

substituting the values,

E' = V / ( 2d )

E' = 1/2 ( V /d )

E' = 1/2 E

hence we can conclude that

Electric field between plates will be halved as it was before.

Learn more about Electric field between plates here:

<u>brainly.com/question/14788793</u>

#SPJ4

7 0
2 years ago
20 POINTS!!!!!!!!!!!!!! How do the charges compare when two objects are charged through friction?
Nataly_w [17]
The answer is A. Opposites attract, hence the attraction during friction. Balloons and hair would be a great example.
8 0
3 years ago
Read 2 more answers
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