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Andrei [34K]
4 years ago
5

How to simplify sinθ(1+cot^2 θ)

Mathematics
1 answer:
AVprozaik [17]4 years ago
6 0

\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1 ~\hfill 1+cot^2(\theta)=csc^2(\theta) ~\hfill 1+tan^2(\theta)=sec^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(\theta )[1+cot^2(\theta )]\implies sin(\theta )[csc^2(\theta )]\implies sin(\theta )\cdot \left[ \cfrac{1}{sin(\theta )} \right]^2 \\\\\\ sin(\theta )\cdot \cfrac{1^2}{sin^2(\theta )}\implies \cfrac{sin(\theta )}{sin^2(\theta )}\implies \cfrac{1}{sin(\theta )}\implies csc(\theta )

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Maru [420]

Answer:

<em>The large  sample n = 117.07</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

<u><em>Step(ii):-</em></u>

The Marginal error is determined by

M.E = \frac{Z_{0.05} \sqrt{p(1-p)}  }{\sqrt{n} }

0.08 = \frac{2 X \sqrt{0.75(1-0.75)}  }{\sqrt{n} }

Cross multiplication , we get

\sqrt{n}  = \frac{2 X \sqrt{0.75(1-0.75)}  }{0.08 }

√n = \frac{2 X0.4330}{0.08} = 10.825

squaring on both sides , we get

n = 117.07

<u><em>Final answer:-</em></u>

<em>The large  sample n = 117.07</em>

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3 years ago
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Westkost [7]

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Usimov [2.4K]

h(x) = 3x + 5

h(a) = 27


We can write this as 3a + 5 = 27

Now, we just need to solve for a.

<em><u>Subtract 5 from both sides</u></em>

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Now, let's plug 7.33 back into the original equation.

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(x - 3)^2

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7 0
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