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natka813 [3]
3 years ago
7

If h(x)= 3x+5 and h(a) =27, then what is the value of a ?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0

h(x) = 3x + 5

h(a) = 27


We can write this as 3a + 5 = 27

Now, we just need to solve for a.

<em><u>Subtract 5 from both sides</u></em>

3a = 22

<em><u>Divide 3 from both sides.</u></em>

a = 7.33

Now, let's plug 7.33 back into the original equation.

3 * 7.33 + 5 = 27

22 + 5 = 27

27 = 27 √ this is correct

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The 13-in. by 9-in. rectangle where the food listings fit has an area of 13 in. * 9 in. = 117 in.^2

Adding 48 in.^2 for the border, the total area of the menu with the border will be 117 in.^2 + 48 in.^2 = 165 in.^2

The border has to have uniform width around the menu. We need to find the width of the border. Let the border be x inches wide. Then since you have a border at each of the 4 sides, the border will add 2x to the length of the rectangle and 2x to the width of the rectangle. The menu will have a length of 2x + 13 and a width of 2x + 9. The area of the larger rectangle must by 165 in.^2. The area of a rectangle is length times width, so we get our equation:

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4x^2 + 18x + 26x + 117 = 165

4x^2 + 44x + 117 = 165

4x^2 + 44x - 48 = 0

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x^2 + 11x - 12 = 0

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x + 12 = 0 or x - 1 = 0

x = -12 or x = 1

The solution x = -12 is not valid for our problem because the width of a border cannot be a negative number. Discard the negative solution.

The solution is x = 1.

Answer: The border is 1 inch wide.

Check. Add 2 inches to the length and width of the food listings rectangle to get 15 inches by 11 inches. A = 15 in. * 11 in.= 165 in.^2. Now subtract the area of the border, 48 in.^2, 165 in.^2 = 48 in.^2 = 117 in.^2, and you get the area of the 13-in. by 9-in. rectangle. This shows that our solution is correct.

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