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miv72 [106K]
4 years ago
12

Where in the body does neutral, acidic and basic (alkaline) solutions usually exist?

Physics
1 answer:
tekilochka [14]4 years ago
3 0
Circulatory system blood
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If the wavelength of a wave of light is 4.57x10^-9 m what is the frequency
alexandr402 [8]

Answer:

6.5646\times 10^{16}~ \text{Hz}

Explanation:

\text{Frequency,}~ f= \dfrac{c}{\lambda} = \dfrac{3\times 10^8 }{4.57 \times 10^{-9}} = 6.5646\times 10^{16}~ \text{Hz}

5 0
3 years ago
Tennis balls traveling at greater than 100 mph routinely bounce off tennis rackets. At some sufficiently high speed, however, th
Kipish [7]

Answer:

Probability of tunneling is 10^{- 1.17\times 10^{32}}

Solution:

As per the question:

Velocity of the tennis ball, v = 120 mph = 54 m/s

Mass of the tennis ball, m = 100 g = 0.1 kg

Thickness of the tennis ball, t = 2.0 mm = 2.0\times 10^{- 3}\ m

Max velocity of the tennis ball, v_{m} = 200\ mph = 89 m/s

Now,

The maximum kinetic energy of the tennis ball is given by:

KE = \frac{1}{2}mv_{m}^{2} = \frac{1}{2}\times 0.1\times 89^{2} = 396.05\ J

Kinetic energy of the tennis ball, KE' = \frac{1}{2}mv^{2} = 0.5\times 0.1\times 54^{2} = 154.8\ m/s

Now, the distance the ball can penetrate to is given by:

\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}

\bar{h} = \frac{h}{2\pi} = \frac{6.626\times 10^{- 34}}{2\pi} = 1.0545\times 10^{- 34}\ Js

Thus

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}

\eta = 1.52\times 10^{-35}\ m

Now,

We can calculate the tunneling probability as:

P(t) = e^{\frac{- 2t}{\eta}}

P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}

P(t) = e^{-2.63\times 10^{32}}

Taking log on both the sides:

logP(t) = -2.63\times 10^{32} loge

P(t) = 10^{- 1.17\times 10^{32}}

6 0
3 years ago
Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground
trapecia [35]

The correct answer to the question is : A) Tossing it horizontally at a faster speed.

EXPLANATION:

Before going to answer this question, first we have to know the horizontal distance covered by any body when it is fired parallel to the ground.

Let us consider a body of mass m is fired with velocity u parallel to the ground. Let it was projected at a height h from the ground.

Hence, the horizontal distance covered by the projectile is calculated as -

                    Horizontal distance R = u\times \sqrt{\frac{2h}{g}}.

Here, g is known as the acceleration due to gravity.

From above, we see that more is the initial velocity, the more is the horizontal distance covered by it i.e the more is the widest curved path.

Hence, the correct answer to the question is that tossing a ball horizontally at a faster speed will trace out the widest curved path.


6 0
3 years ago
Read 2 more answers
Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t
s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1=\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2) because the derivate of the position is the velocity

V1=12t+3

V2=20+\int\limits^_ {} \,-8t because the integral of the acceleration is the velocity

V2=20-4t^{2}

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with \frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0
3 years ago
Nếu tăng khoảng cách giữa hai điểm lên 4 lần thì lực tương tác tĩnh điện giữa chúng sẽ
ohaa [14]

Answer:

điện giữa chúng s

Explanation:

8 0
3 years ago
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