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hodyreva [135]
3 years ago
11

How many times is a ray of light reflected by 2 plane mirrors placed parallel and facing each other

Physics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

the ray is reflected infinite number of times by 2 plane mirrors placed parallel to each other as each reflected ray would be the incident ray for the other.

Explanation:

the ray is reflected infinite number of times by 2 plane mirrors placed parallel to each other as each reflected ray would be the incident ray for the other.

Placing one mirror at an angle causes reflections to curve.

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A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh
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To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}

P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}

P^2 = \frac{P^2V^2}{c^2}+m^2V^2

P^2 = V^2 (\frac{P^2}{c^2}+m^2)

V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}

V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}

V = 2.81784*10^8m/s

Therefore the height with respect the observer is

l = l_0*\sqrt{1-\frac{V^2}{c^2}}

l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}

l = 0.56m

Therefore the height which the observerd measure for her is 0.56m

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3 years ago
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The charge would be in equilibrium so there would be no charge in the body of the conductor.


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