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daser333 [38]
3 years ago
14

Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground

Physics
2 answers:
trapecia [35]3 years ago
6 0

The correct answer to the question is : A) Tossing it horizontally at a faster speed.

EXPLANATION:

Before going to answer this question, first we have to know the horizontal distance covered by any body when it is fired parallel to the ground.

Let us consider a body of mass m is fired with velocity u parallel to the ground. Let it was projected at a height h from the ground.

Hence, the horizontal distance covered by the projectile is calculated as -

                    Horizontal distance R = u\times \sqrt{\frac{2h}{g}}.

Here, g is known as the acceleration due to gravity.

From above, we see that more is the initial velocity, the more is the horizontal distance covered by it i.e the more is the widest curved path.

Hence, the correct answer to the question is that tossing a ball horizontally at a faster speed will trace out the widest curved path.


Hoochie [10]3 years ago
6 0
<span>Choice B) is would result in the widest curved path
B)tossing it horizontally at a faster speed

If choice A were to occur this would just result in a lesser range ad thus not be as wide.
Choices c and d would only affect the vertical motion and make the path less arched,
because the vertical and horizontal movements in kinematics are indpendant but shared the same time. </span>
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Rasek [7]

Answer:5

Explanation:

a=3

b=4

c=√(a²+b²)

c=√9+16

c=√25

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3 0
3 years ago
A Block slides down an incline that makes an angle of 30? with the horizontal direction. The coefficient of kinetic friction bet
astraxan [27]

Answer:

Acceleration = 2.35 m/s^{2}

Speed = 8.67 m/s

Explanation:

The coefficient of friction , u =0.3

The angle of incline = 30°

The two forces acting on block are weight and friction.

weight along the incline = mg cos60° = \frac{mg}{2} = 0.5 mg

Friction along incline = umg cos30° = mg 0.3\times \frac{\sqrt{3}}{2}

Friction along incline  = 0.26 mg

Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg

Acceleration = \frac{net force}{mass} = 0.24 g = 2.35 m/s^{2}

The height of incline = 8 m

Length of the inclined edge = 16 m

v^{2}=u^{2}+2as

v^{2}= 2\times 0.24 \times 9.8\times 16

v= 8.67 m/s

5 0
4 years ago
A student wearing frictionless in-line skates on a horizontal surface is pushed by a friend with a constant force of 45 N. How f
kiruha [24]
Work is obtained by multiplying the force and the object's displacement. The force and displacement and force should be in the same direction in order to have work. 
                                      W = F x d
                                     d = W / F
Substituting the known values,
                                     d = 352 J / 45 N = 7.82 m
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4 years ago
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Tomtit [17]

Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

         3000m  =   \frac{3000}{1 x 10^{-6} }   = \frac{3  x 10^{3} }{ 1  x  10^{-6} }   = 3 x 10⁻⁹km

b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

              1yd  = 0.91m

              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give \frac{2.73}{1 x 10^{-6} }   = 2.73 x 10⁶μm

           

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