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Phantasy [73]
4 years ago
12

The graph of y=6-[sqrt(4-3x)] contains which point?

Mathematics
1 answer:
elena-14-01-66 [18.8K]4 years ago
4 0

Given y=6-[sqrt(4-3x)], focus on the sqrt function:  sqrt(4-3x).  Since the input of this function cannot be negative, any x-value used must pass the test 4-3x>0.  This is equivalent to 4>3x, or 3x<4, or x < 4/3.  This eliminates choice E.

Second, if the y value is an integer, then sqrt(4-3x) must be an integer.  

Checking answers A through D:  

A:  sqrt(4-3) = sqrt(1) = 1 (OK)        Then y=6-[sqrt(1)] = 5  (NO)

B:  sqrt(4-0) = 2 (OK)                     Then y=6-2 = 4   (NO)

C:  sqrt(4-0) = 2 (OK)                      Then y=6-2 = 4 (NO)

D:  sqrt(4-15) Not OK; eliminate

Correct answer:  F:  None of the above answers are correct

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Cerebral $500 for four years at 3% interest compounded annually use the formula to calculate the total amount she will have to p
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Since we're doing compound interest for four years it will be simpler than daily.
In case you didn't know the formula, here it is: A = P (1 +r/n)^(nt)
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