All categories

3 years ago

Which describes the number and type of roots of the equation x^3 + 121x = 0?

Mathematics

1 answer:

shusha [124]3 years ago

6 0

Answer:

b; 1 real root and 2 imaginary roots

Step-by-step explanation:

From here, we have

x(x^2 + 121) = 0

x = 0 (1 real root)

x^2 + 121 = 0

x^2 = -121

x = √(-121) (2 imaginary roots)

so is would be two complex numbers from above

You might be interested in

There are 624 students at Lincoln Middle School. 78 of the students are left-handed. What percent of students at Lincoln Middle

Leto [7]

22% are right handed

7 0

3 years ago

The two-way table below displays demographic data for the passengers aboard the Titanic.

meriva

Answer:

About 72%

Step-by-step explanation:

All you have to do is divide the number of children who traveled in third class (79) by the total number of children (109)

79/109=.724770642 OR 72%

5 0

3 years ago

Read 2 more answers

If f(x)=-3x-2, find each value.<br> 1. f(3)

prohojiy [21]

Answer:

-11

Step-by-step explanation:

If F of x is 3, you would implement it into the equation. F(3)= -3(3)-2= -9-2= -11

5 0

3 years ago

A person pay $3500 for 42 lawn mowers, then sells each lawnmower for $99. How much profit does the store make?

masya89 [10]

Answer:

$658

Step-by-step explanation:

42 x 99 = 4,158

4,158 - 3,500 = 658

5 0

3 years ago

PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago