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3 years ago

10

Assume that ∠A is an acute angle. If sin A = 0.994, use a calculator to find the measure of ∠A to two decimal places. The mea

sure of ∠A = _ degrees.

1 answer:

Sedbober [7]3 years ago

8 0

Basically, you are looking for the ARC SINE of .994 which is
83.72 Degrees
You could also use an online calculator:
http://www.1728.org/trigcalc.htm

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ryzh [129]

For this problem, all you need to do is find the three #'s that add up to 156.

So, lets look at the answers and add them up.

A. 50, 52, 54

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51 + 52 + 53 = 156

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49 + 50 + 51 = 150

D. 49,51,53

49 + 51 + 53 = 153

We get the answers (50,52,54) and (51,52,53)

Now, consecutive numbers are numbers that in order, like 1,2,3.

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3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

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we now look for the hypotenuse of the right angled triangle

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sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

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