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iogann1982 [59]
3 years ago
12

REASONING A rectangular box for a new product is designed in such a way that

Mathematics
1 answer:
dsp733 years ago
6 0

Answer:

(2x+3) y (3x+5)

Step-by-step explanation:

For this exercise we have that the volume is

V = 6x ^ 3 + 31X ^ 2 + 53x + 30

H = X + 2

The formula for the Volume its

V = H * L * W

for find L and W (width and length) we divide V / H = L * W

So,

\frac{V}{H} =\frac{6X^{3}+31X^{2}+53X+30 }{X+2}=(2x + 3) * (3x + 5)\\

this division is in the attachment

so, L * W = (2x + 3) * (3x + 5)

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7x+9y=-41 and x+3y=1. Solve system of equations
galben [10]

9514 1404 393

Answer:

  (x, y) = (-11, 4)

Step-by-step explanation:

You can subtract 3 times the second equation from the first to eliminate y.

  (7x +9y) -3(x +3y) = (-41) -3(1)

  4x = -44

  x = -11

Substituting into the second equation gives ...

  -11 +3y = 1

  3y = 12

  y = 4

The solution is (x, y) = (-11, 4).

7 0
3 years ago
Can someone help me with this please?
garri49 [273]

Answer:

EASY PEASY

Step-by-step explanation:

(5x-5)=(4x+10){being corresponding angles}

solve it now by arranging like

5x-4x=10+5

done

and the second is co-interior

8 0
2 years ago
Add the two expressions.<br> 32 – 4 and 2z + 5<br><br><br> Pls help quick!
alexgriva [62]

Answer:

2z + 33

Step-by-step explanation:

Add like terms like below:

(32 - 4) + (2z + 5) = 28 + 2z + 5

Combine like terms again:

(28 + 5) + 2z = 33 + 2z or 2z + 33

7 0
3 years ago
Find the coordinates of the missing endpoint if P is the midpoint of Line Segment NQ.
dimaraw [331]
  • Midpoint formula is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) .
<h3>19.</h3>

So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such: \frac{x+2}{2}=5 From here we can solve for the x-coordinate of Q.

Firstly, multiply both sides by 2: x+2=10

Next, subtract both sides by 2 and your x-coordinate is x=8

With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

\frac{y+0}{2}=2\\ y=4

<u>Putting it together, the missing endpoint is (8,4).</u>

<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>

<h3>20.</h3>

\frac{x+5}{2}=6\\ x+5=12\\ x=7

\frac{y+4}{2}=3\\ y+4=6\\ y=2

<u>The missing endpoint is (7,2).</u>

<h3>21.</h3>

\frac{x+3}{2}=-1\\ x+3=-2\\ x=-5

\frac{y+9}{2}=5\\ y+9=10\\y=1

<u>The missing endpoint is (-5,1).</u>

8 0
3 years ago
Is 4.5 same as 4.50?
Softa [21]

Answer:

Yes

Step-by-step explanation:

0s after all the decimals do not count

4 0
3 years ago
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