All categories

3 years ago

Find the first 3 terms of arithmetic sequence if t5=-154 and t9=-274. find t1, t2, t3

Mathematics

1 answer:

777dan777 [17]3 years ago

4 0

Answer: t1 = -34; t2 = -64; t3 = -94

d is the distance between numbers (d > 0)

we have:

t5 = t1 + 4d = -154

t9 = t1 + 8d = -274

we have the equations:

t1 + 4d = -154

t1 + 8d = -274

<=> t1 = -34

d = -30

with t1 = -34 and = -30 => t2 = -34 - 30 = -64

t3 = -64 - 30 = -94

Step-by-step explanation:

You might be interested in

A) work out (8 x 10^-3) x (2 x 10^-4). Give your answer in standard form.

mafiozo [28]

Step-by-step explanation:

$A) \\ (8 \times {10}^{ - 3} ) \times (2 \times {10}^{ - 4} ) \\ = 8 \times 2 \times {10}^{ - 3} \times {10}^{ - 4} \\ = 16 \times {10}^{ - 3 - 4} \\ = 16 \times {10}^{ - 7} \\ = 1.6 \times {10}^{ - 6} \\ \\ B) \\ (6 \times {10}^{ 2} ) \div (3\times {10}^{ - 5} ) \\ \\ = \frac{6 \times {10}^{ 2}}{3\times {10}^{ - 5}} \\ \\ = \frac{2\times {10}^{ 2}}{ {10}^{ - 5}} \\ \\ = 2 \times {10}^{ 2 + 5} \\ \\ = 2 \times {10}^{7} \\$

4 0

3 years ago

I pick a ball from a bag, replace it and then pick

Korolek [52]

Answer:

It should be 50%

Step-by-step explanation:

It should be 50% because there are 12 yellow balls, so it should be 50%.

Hope it helps you

7 0

3 years ago

20+20+20+20+20-10-10/5

antiseptic1488 [7]

Answer:

The answer to the question is 16

Step-by-step explanation:

To find out the answer all we need to do is:-

Do addition for the first set of 20's. ( Or Multiply The 20's)

20 + 20 + 20 + 20 + 20 (or) Number of 20's = 5

= 40 + 40 + 20 The number = 20

= 80 + 20 Therefore, 20 × 5 = 100

= 100

-----------------------------------------------------------------------------------------------------------

Number of tens = 2 Therefore, 10 × 2 = 20

The number = 10

Now, we subtract 100 - 20 = 80.

-----------------------------------------------------------------------------------------------------------

We have 80 and now we divide the number by 5

If we do that we get the answer as 16.

I hope this answer helps.

5 0

3 years ago

Read 2 more answers

Customers experiencing technical difficulty with their Internet cable hookup may call an 800 number for technical support. Itake

Paladinen [302]

Answer:

(A) The percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B) The problem solving time will be 50% as long as the difference between the two end points is 5.75.

(D) Mean = 6.25 minutes, Standard deviation = 3.32 minutes

Step-by-step explanation:

Let the random variable X represent the time it takes the technician to resolve the problem.

The random variable X follows an Uniform distribution with parameters a = 0.50 minutes and b = 12 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(A)

Compute the probability that the problems takes more than 5 minutes to resolve as follows:

$P(X>5)=\int\limits^{12}_{5}{\frac{1}{12-0.50}}\, dx$

$=\frac{1}{11.50}\cdot \int\limits^{12}_{5}{1}\, dx \\\\=\frac{1}{11.50}\cdot [x]\limits^{12}_{5}\\\\=\frac{1}{11.50}\cdot [12-5]\\\\=\frac{7}{11.50}\\\\=0.608696\\\\\approx 0.6087$

Thus, the percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B)

Let the middle 50% of the problem-solving times be between u and v.

Then,

P (u < X < v) = 0.50

$\int\limits^{v}_{u}{\frac{1}{12-0.50}}\, dx=0.50\\\\\frac{1}{11.50}\cdot \int\limits^{v}_{u}{1}\, dx=0.50\\\\\frac{v-u}{11.50}=0.50\\\\(v-u)=5.75$

Thus, the problem solving time will be 50% as long as the difference between the two end points is 5.75.

(C)

The interval in which the technician can solve the problem is 30 seconds to 12 minutes.

So, the values of a and b in minutes is:

a = 30 seconds = 0.50 minutes

b = 12 minutes.

(D)

The mean time is:

$\mu=\frac{a+b}{2}=\frac{0.50+12}{2}=6.25\ \text{minutes}$

The standard deviation of the time is:

$\sigma=\sqrt{\frac{(b-a)^{2}}{12}}=\sqrt{\frac{(12-0.50)^{2}}{12}}=3.3197\approx 3.32\ \text{minutes}$

5 0

3 years ago

What is 12 bittlion÷4.76billion

Fittoniya [83]

The answer is2.52100840336 if right thanxs

6 0

3 years ago