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2 years ago

Find the first 3 terms of arithmetic sequence if t5=-154 and t9=-274. find t1, t2, t3

Mathematics

1 answer:

777dan777 [17]2 years ago

4 0

Answer: t1 = -34; t2 = -64; t3 = -94

d is the distance between numbers (d > 0)

we have:

t5 = t1 + 4d = -154

t9 = t1 + 8d = -274

we have the equations:

t1 + 4d = -154

t1 + 8d = -274

<=> t1 = -34

d = -30

with t1 = -34 and = -30 => t2 = -34 - 30 = -64

t3 = -64 - 30 = -94

Step-by-step explanation:

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Serhud [2]

Answer:

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Step-by-step explanation:

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2 years ago

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x

Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

$0 = 2 {x}^{2} + 3x - 8$

This is the same as,

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Comparing to

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We have

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$x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

We substitute the values to get,

$x = \frac{ - 3\pm \: \sqrt{ {3}^{2} - 4(2)( - 8)} }{2(2)}$

$x = \frac{ - 3\pm \: \sqrt{ 73} }{4}$

The positive root is

$x = \frac{ - 3 + \: \sqrt{ 73} }{4} = 1.39$

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2 years ago

How do you solve 3^(4x) = 3^(5-x)?

trasher [3.6K]

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2 years ago