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3 years ago

What is the area of the composite figure shown?

Mathematics

1 answer:

Arlecino [84]3 years ago

8 0

Answer:

the area is 55.2m

Step-by-step explanation:

a= 24m b= 1.8*3.5=6.3m c=24.9m

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Please help.... what is it’s measure

Olegator [25]

right

Answer:

90°

Step-by-step explanation:

Type of angle foremd= right

Measure = 40° + 50° = 90°

8 0

2 years ago

Read 2 more answers

Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c

nadya68 [22]

Answer:

$A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right]$ message SHOW_ME_THE_MONEY_

Step-by-step explanation:

The matrix

$A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\$

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message Decoded message message in letters by association

11 52 19 8 S H

-8 -9 15 23 O W

-13 -39 0 13 _ M

5 20 5 0 E _

12 56 20 8 T H

5 20 5 0 E _

-2 7 13 15 M O

9 41 14 5 N E

25 100 25 0 Y _

Then the message decoded is SHOW_ME_THE_MONEY_

3 0

2 years ago

What is the fraction eight twentieths in its simplest form?

Nostrana [21]

Both the numerator and denominator are divisible by 4, meaning that when they are both divided by this number they wll be in their simplest form.

e.g. 8/4=2 and 20/4=5

Therefore the simplest form is 2/5

7 0

2 years ago

Giovanni purchased 25tickets to an airshow. the cost of an adult's ticket is $14 and the child's ticket is $8. if the total cost

Masteriza [31]

Giovanni purchased 20 adult tickets and 5 child's tickets.

Step-by-step explanation:

Let,

x = Adult tickets

y = Child's tickets

According to given statement;

x+y=25 Eqn 1

One adult ticket costs $14 and one child ticket costs $8, therefore,

14x+8y=320 Eqn 2

$Multiplying\ Eqn\ 1\ by\ 8\\8(x+y=25)\\8x+8y=200\ Eqn\ 3\\Subtracting\ Eqn\ 3\ from\ Eqn\ 2\\(14x+8y)-(8x+8y)=320-200\\14x+8y-8x-8y=120\\6x=120\\Dividing\ both\ sides\ by\ 6\\\frac{6x}{6}=\frac{120}{6}\\x=20$