To find the perimeter, the equation is (w2 + l2 = p)
Where w is width and l is length and p is perimeter.
If you have the width, then you double it for both widths.
Then subtract that number from the perimeter.
150-60 = 90
90 is the remaining number for the lengths. Since both lengths needs to be equal, you split the 90. 45.
You length equals 45.
45(2) + 30(2) = Perimeter of 150.
Your answer is 45.
When a line changes position from one point to another, the movement is referred to as transition.
<em>Bobby does not have enough information to make a valid conclusion.</em>
The movements of the lines are given as:
<em>Line 1: 3 units up and 8 units right</em>
<em>Line 2: 8 units down and 3 units right</em>
The given information only describes the movement of both lines, but does not give details about the initial relationship between the lines.
<em>Hence, no valid conclusion can be made with the given information.</em>
Read more about lines at:
brainly.com/question/5830373
Answer:a
Step-by-step explanation:did it
Answer:
a) 9*π or approx 28.26
b) ∡CRB=100°
Step-by-step explanation:
As known for secants crossing each other inside the circle is coorect the following:
BR*RD=AR*RC
=> 3*RD=4*4.5
RD=6
The diameter of the circle with center P is BD=BR+RD=3+6=9
So the radius of the circle is D/2=9/2=4.5
As known the circumference of any circle can be calculated as
C=2*π*r , where r is the circle's radius
So C=2*4.5*π=9*π= approx 3.14*9=28.26
b) ∡CRB=∡ARD= (arcBC+arcAD), where arcBC and arcAD smaller arcs
BD is the circle's diameter, so arc BD=180°
So arcBC=180°-arcCOD=180°-100°=80°
Similarly arcBD=180°
arcAD=180°-arcBSA=180°-60°=120°
∡CRB= (80°+120°)/2=100°
Answer:
Each marker will be exactly <u>103</u> miles apart.
Step-by-step explanation:
It is given that Ian wants to run 412 miles and has set up 3 markers the same distance apart.
Between the start and end of run, the 3 separate markers will divide the 412-mile distance into 4 equal segments.
So each segment = 412/4 = 103 miles
Each marker will be exactly <u>103</u> miles apart.
