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3 years ago

4x + 1 + x = -4 Can anybody help me solve this ?

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

Answer:

X=-5/3 or X=-1 2/3 or X=-1.66

Step-by-step explanation:

Combine like terms:

4x+1+x=-4

-x -x

3x+1=-4

-1 -1

3x=-5

Divide by 3:

3x/3=-5/3

X=-5/3

X=-1 2/3

X=-1.66

ValentinkaMS [17]3 years ago

7 0

Answer:

Simplify the equation

Step-by-step explanation:

4x + 1 + x + -4

= 4x + x + 1 - 4

= 5x + -3

= 5x - 3

Hope this helps

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2 years ago

GEOMETRY! PLEASE SHOW YOUR WORK. (updated picture)

Orlov [11]

Given:

The base of the given triangle has two part:

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Right ( right side of the hypotenuse) = x

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By Altitude rule we know that, the altitude of a triangle is mean proportional between the right and left part of the hypotenuse,

$\frac{left}{altitude} =\frac{altitude}{right}$

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$\frac{25}{60} =\frac{60}{x}$

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2 years ago

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Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

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