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Andru [333]
2 years ago
15

Please help me wit dis no one would help and i really need help

Mathematics
1 answer:
lukranit [14]2 years ago
5 0

(4) 64 tiles,   (5) \mathrm{N}=\mathrm{s}^{2},   (6)  N^{2}=S^{4}

Step-by-step explanation:

Given data: Side length of square tile = 1 ft

(4)  Side length of square pool = 8 ft

\text {Number of tiles} =\frac{\text { Area of square pool }}{\text { area of square tile }}

=\frac{8 \times 8}{1 \times 1}

= 64

Hence 64 tiles needed for the border.

(5) Suppose number of square tiles be N and side of square tub is s ft.

So, N = \frac{s \times s}{1 \times 1}

\Rightarrow N=s^{2}

So, the expression is \mathrm{N}=\mathrm{s}^{2}.

(6) The equivalent expression is \mathrm{N}^{2}=\mathrm{S}^{4}.

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Help plz with this math problem. I’m so confused
Lunna [17]

Slope-intercept form is written as <em>y = mx + b</em>, where m is the slope and b is the y-intercept.

From this graph we should determine two points so we can work out the slope. Let's take points (3, -4) and (6, -2).

                                       

The equation to find the slope is:

m = \frac{y2 - y1}{x2 - x1}

Let's substitute in our values:

m = \frac{-2 - -4}{6 - 3}

Remember that two negatives make a positive, let's solve for m:

m = \frac{2}{3}

Okay, now we have the value of m. Now we need the value of b. We can determine this by looking at the graph and looking where the line passes through the y-axis. In this graph, we can see the line pass through the y-axis at point (0, -6).

Therefore we can determine that b = -6.

Let's substitute our value for m and our value for b into the slope-intercept formula:

y = mx + b

<u>y = </u>\frac{2}{3}<u>x + -6</u>

There's your final answer! I hope this helps, have a great night. :)

6 0
3 years ago
Write each number as a product using the GCF as a​ factor, and apply the Distributive Property.
Rasek [7]

The distributive property: a(b + c) = ab + ac.

Factors of 38: 1, 2, 19, 38

Factors of 57: 1, 3, 19, 57

GCF(38, 57) = 19

38 + 57 = 19 · 2 + 19 · 3 = 19(2 + 3)

6 0
3 years ago
Which similarity statement describe the relationship between the two triangle? Check all that apply
anzhelika [568]

Answer:

If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar

8 0
3 years ago
The 20% tip on a $8 sandwich ​
melamori03 [73]

Answer:

Tip of $1.60

The total is $9.60

Step-by-step explanation:

(20% × $8) + $8

$1.60 + $8

$9.60

5 0
3 years ago
Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0
3 years ago
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