Question

a catapult launches a boulder with an upward velocity of 122 feet per second the height of the boulder H in feet after T seconds is given by the function h x 2 equals negative 16t ^ 2 + 122 t + 10 how long does it take the boulder to reach maximum height what is the boulders maximum height

Answer 1

Answer: Reaches a maximum height of 242.56 feet after 3.81 seconds.

i think

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Answer 2

It will reach about 242.56 feet after 3.81 seconds.

In this quadratic equations, we have the following values.
A = -16, B = 122 and C = 10

The expression for x-value of the vertex is (-b/2a). Doing this will give you the time of 3.8125 seconds.

Just input that value back into the equation and you will get the max height of 242.56 feet.