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qaws [65]
3 years ago
12

a catapult launches a boulder with an upward velocity of 122 feet per second the height of the boulder H in feet after T seconds

is given by the function h x 2 equals negative 16t ^ 2 + 122 t + 10 how long does it take the boulder to reach maximum height what is the boulders maximum height
Mathematics
2 answers:
Archy [21]3 years ago
6 0

Answer: <em><u>Reaches a maximum height of 242.56 feet after 3.81 seconds.</u></em>

<em>i think </em>

<em>bing bong bing bing bong bye</em>

SVETLANKA909090 [29]3 years ago
5 0
It will reach about 242.56 feet after 3.81 seconds.

In this quadratic equations, we have the following values.
A = -16, B = 122 and C = 10

The expression for x-value of the vertex is (-b/2a). Doing this will give you the time of 3.8125 seconds.

Just input that value back into the equation and you will get the max height of 242.56 feet. 
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