The exact calculations:
Principal, P=3000
interest rate = 33% per year
Period, t=10 years
Future value
Interest
= future value - principal
= 81337.92-3000
=
78337.92 (to the nearest cent)
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
1. Participial
2. Gerund
3.participal
4.participal
4.infinitive
Answer:
75%
Step-by-step explanation:
or since a percent is a decimal then 0.75
9514 1404 393
Answer:
14.1 years
Step-by-step explanation:
Use the compound interest formula and solve for t. Logarithms are involved.
A = P(1 +r/n)^(nt)
amount when P is invested for t years at annual rate r compounded n times per year.
Using the given values, we have ...
13060 = 8800(1 +0.028/365)^(365t)
13060/8800 = (1 +0.028/365)^(365t) . . . . divide by P=8800
Now we take logarithms to make this a linear equation.
log(13060/8800) = (365t)log(1 +0.028/365)
Dividing by the coefficient of t gives us ...
t = log(13060/8800)/(365·log(1 +0.028/365)) ≈ 0.171461/0.0121598
t ≈ 14.1
It would take about 14.1 years for the value to reach $13,060.
