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Oksana_A [137]
3 years ago
8

Two regular hexagons have sides in the ratio 3:5. The area of the smaller hexagon is 81 m2. What is the area of the larger hexag

on
Mathematics
1 answer:
Aliun [14]3 years ago
4 0
If the sides are in the ratio of 5:3 then the area will increase by a factor of:(5 / 3) ^2
(5 / 3)^2 = <span> <span> <span> 2.777777777 </span> </span> </span>
Area of small hexagon = 81
Area of larger hexagon = 81 * 2.777777777
Area of larger hexagon = 225 square meters

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What is the solution to = n/4 -12.4?
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Step-by-step explanation:

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Which measurement that does not belong 3500 km, 3.5 m, 350cm, 3500mm
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2 years ago
A Social welfare association decides to supply drinking water for the flood affected people. The drinking water is filled in a c
pickupchik [31]

Answer:

1,499 liter

Step-by-step explanation:

The rest of the question is:

each is in the shape of a cylinder of radius 21 cm and height is 50 cm.

==============================================================

The quantity of water left in the tanker after distribution

= Total quantity - Distributed quantity

Total quantity = Volume of the giving figure

                       = Volume of the cylinder + volume of 2 hemispheres

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

L = 4.2 and radius = r = 0.5 * diameter = 0.5 * 1.2 = 0.6

Volume of cylinder = π r² L = (22/7) * 0.6² * 4.2 = 4.752 m³

Volume of 2 hemispheres = 2*0.5 * (4/3) π r³ = (4/3) * (22/7) * 0.6³

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Total volume = 4.752 + 792/875 = 198/35 ≈ 5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

Distributed quantity = 60 * π r² L = 60 * (22/7) * 21² * 50 = 4,158,000 cm³

Since 1 m³= 1,000,000 cm³

Distributed quantity = 4,158,000 cm³ = 4.158 m³

The quantity of water left in the tanker after distribution =

 = 198/35 - 4.158 ≈ 1.499 m³

Since 1 m³= 1,000 liter

The quantity of water left in the tanker after distribution =

  =  1.499 m³ = 1.499 * 1000 = 1,499 liter

7 0
3 years ago
Read 2 more answers
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