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Illusion [34]
4 years ago
10

Which translation maps the vertex of the graph of the function f(x) = x2 onto the vertex of the function g(x) = -8 + x^2 + 7 ?

Mathematics
1 answer:
Ad libitum [116K]4 years ago
4 0

Answer:

The function translated 4 units right and 9 units down

The third answer

Step-by-step explanation:

* To solve the problem you must know how to find the vertex

  of the quadratic function

- In the quadratic function f(x) = ax² + bx + c, the vertex will

 be (h , k)

- h = -b/2a and k = f(-b/2a)

* in our problem

∵ f(x) = x²

∴ a = 1 , b = 0 , c = 0

∵ h = -b/2a

∴ h = 0/2(1) = 0

∵ k = f(h)

∴ k = f(0) = (0)² = 0

* The vertex of f(x) is (0 , 0)

∵ g(x) = -8x + x² + 7 ⇒ arrange the terms

∴ g(x) = x² - 8x + 7

∵ a = 1 , b = -8 , c = 7

∴ h = -(-8)/2(1) = 8/2 = 4

∵ k = g(h)

∴ k = g(4) = (4²) - 8(4) + 7 = 16 - 32 + 7 = -9

∴ The vertex of g(x) = (4 , -9)

* the x-coordinate moves from 0 to 4

∴ The function translated 4 units to the right

* The y-coordinate moves from 0 to -9

∴ The function translated 9 units down

* The function translated 4 units right and 9 units down

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(09.01)
ratelena [41]

Answer:

y = x2 - 4x + 2 ; y=x²-4

Step-by-step explanation:

Axis of symmetry = - b /2a

y=x²-2

a = 1 ; b = - 2

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x = 2/2 = 1

y = x2 - 4x + 2

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x = - (-4) / 2(1)

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x = - 4 / 2(1)

x = - 4/2 = - 2

y=x²-4

a = 1 ; b = - 4

x = - (-4) / 2(1)

x = 4/2 = 2

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