What would be the amount of the bill if the phone is not used during the month?

Mathematics

1 answer:

poizon [28]3 years ago

5 0

Answer:

im pretty sure its 25

Step-by-step explanation:

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What are the zeros of f(x)= x^2+x-30

Westkost [7]

Answer:

Step-by-step explanation:

The zeros of the function is the roots and solutions. To find them, factor the equation into two binomials.

$x^2 + x -30\\(x+6)(x-5)$

To solve, set each binomial to 0 and solve for x.

x+6 = 0

x = -6

x-5=0

x=5

8 0

3 years ago

Answer correctly and i’ll mark brainliest, pls help

snow_lady [41]

Answer:

22.5% increase.

Step-by-step explanation:

Because her collection grows by 9, that means it increases by 9/40 total. As a decimal, this would be 0.225. Then, as a percent you multiply that by 100 to get 22.5%. Pilar's collection increased by 22.5%

8 0

3 years ago

Read 2 more answers

Explain how to find surface area please... as well as include the formula for finding it. Thank you.

sladkih [1.3K]

1. Surface area of rectangular prism = 2(lb+bh+lh)

Ans = 2(3*2 + 2*4 + 3*4) = 2(6+8+12) = 52 in^2
Fourth option

2. Length of cube = x feet
Surface area = 6x²
Fourth option

3. Surface area of cylinder = πr(2h+r)

Ans = 3.14*1(2*15+1) = 97.34 cm²
second option

4. Same formula as 1
Ans = 2(10*8 + 8*12 + 10*12) = 2(80+96+120) = 592 in²
fourth option

8 0

3 years ago

Find the area of the region in the first quadrant bounded on the left by the y-axis, below by the line y equals one third x co

bonufazy [111]

Answer:

The bounded area is: $\frac{73}{6}\approx 12.17$

Step-by-step explanation:

Let's start by plotting the functions that enclose the area, so we can find how to practically use integration. Please see attached image where the area in question has been highlighted in light green. The important points that define where the integrations should be performed are also identified with dots in darker green color. These two important points are: (2, 6) and (3, 1)

So we need to perform two separate integrals and add the appropriate areas at the end. The first integral is that of the difference of function y=x+4 minus function y=(1/3)x , and this integral should go from x = 0 to x = 2 (see the bottom left image with the area in red:

$\int\limits^2_0 {x+4-\frac{x}{3} } \, dx =\int\limits^2_0 {\frac{2x}{3} +4} \, dx=\frac{4}{3} +8= \frac{28}{3}$

The next integral is that of the difference between $y=-x^2+10$ and the bottom line defined by: y = (1/3) x. This integration is in between x = 2 and x = 3 (see bottom right image with the area in red: