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Assoli18 [71]
3 years ago
6

Rearrange x=3g+2 to make g the subject

Mathematics
1 answer:
STatiana [176]3 years ago
7 0
G=1/3x+-2/3
hope this helps!
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Three freinds each have some ribbon. carol has 42 inches of ribbon, tino has 2.5 feet of ribbon, and baxter has 1.5 yards of rib
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Hi there! 3 feet = 1 yard, 12 inches = 1 foot and 36 inches = 1 yard. All we have to do is change them up into different units by doing a bit of multiplication, division, maybe mental math, and even proportions if you know how to do them. Regardless on what you do, if you do it correctly, here are what your answers should be for each unit.


Inches

Carol: 42 inches
Tino: 30 inches
Baxter: 54 inches

Feet:

Carol: 3.5 feet
Tino: 2.5 feet
Baxter: 4.5 feet

Yards:

Carol: 1 1/6 yards
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Baxter: 1 1/2 yards
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Sentence using the word compound
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two fractions with different denominators have a sum of 7/12 what are two possible addends that results in this sum
yawa3891 [41]
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8 0
3 years ago
Read 2 more answers
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
Please help with this fast
vitfil [10]

Answer:

repost it, I cant see all of the question

3 0
3 years ago
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