Given end points of diameter,
(x1,y1)=(-3,-4)
(x2,y2)=(0,0)
Now,
the equation of circle is,
(x-x1)(x-x2)+(y-y1)(y-y2)=0
or, (x+3)(x-0)+(y+4)(y-0)=0
or, x^2 +3x +y^2 +4y =0
or, x^2 +y^2 +3x + 4y=0
which is in the form of x^2 +y^2 +2gx +2fy + c=0
where,
g=3/2
h=2
c=0
Now,
The formula is pi*r^2*h/3
your answer would have to be B
f(x)=x²-1
g(x)=2x-3
f(x)*g(x)=(x²-1)*(2x-3)-----------> <span>this function exists for all real numbers</span>
the answer is the interval (-∞,∞)
using a graph tool see the attached figure
Answer:
12x + 6
Step-by-step explanation:
3(4x + 2)
you distribute the 3 to 4x and 2
12x + 6
hope this helps
You're looking for something like y=2x+3 and 2y=4x+6?
