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VMariaS [17]
2 years ago
9

Two cars start moving from the same point. one travels south at 48 mi/h and the other travels west at 20 mi/h. at what rate is t

he distance between the cars increasing four hours later?
Mathematics
1 answer:
timofeeve [1]2 years ago
3 0
<span>Two cars start moving from the same point. one travels south at 48 mi/h and the other travels west at 20 mi/h. at what rate is the distance between the cars increasing four hours later? so its 400%</span>
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Use elimination to find the solution to the system of equations. 4x+2y=34 5x-6y=34
Colt1911 [192]

Answer:

Let's solve for x.

4x+2y=345x−6y

Step 1: Add -345x to both sides.

4x+2y+−345x=345x−6y+−345x

−341x+2y=−6y

Step 2: Add -2y to both sides.

−341x+2y+−2y=−6y+−2y

−341x=−8y

Step 3: Divide both sides by -341.

−341x

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−341

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8

341

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Step-by-step explanation:

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7/10

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Step-by-step explanation:

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Opposite angles of a Quadrilateral are Supplementary.

\therefore \: \angle A + \angle C = 180° \\  \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\  \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x =  \frac{176}{4}  \\ \therefore \: x =  44 \\  \\  m\angle A  = (2x + 3) \degree \\  = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle A  =91 \degree}} \\  \\ m\angle  C = (2x + 1) \degree \\  = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle   C=89\degree}}  \\  \\ m\angle  D= (x - 10) \degree \\  = (44 - 10) \degree \\  \huge \red{ \boxed{ \therefore \: m\angle  D =34\degree}}  \\  \\ similarly \\  \\  \huge \red{ \boxed{ \therefore \: m\angle  B  = 146\degree}}   \\  \\

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