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VMariaS [17]
3 years ago
9

Two cars start moving from the same point. one travels south at 48 mi/h and the other travels west at 20 mi/h. at what rate is t

he distance between the cars increasing four hours later?
Mathematics
1 answer:
timofeeve [1]3 years ago
3 0
<span>Two cars start moving from the same point. one travels south at 48 mi/h and the other travels west at 20 mi/h. at what rate is the distance between the cars increasing four hours later? so its 400%</span>
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-9(y+12)=4(-7y-8)<br> Solve for y
miv72 [106K]

-9(y + 12) = 4(-7y -8)

Use the distributive property:

-9y - 108 = -28y -32

Add 32 to both sides:

-9y - 76 = -28y

Add 9y to both sides:

-76 = -19y

Divide both sides by-19

Y = 4

5 0
3 years ago
Solve the following equations for x, and give evidence that your solutions are correct (x/2)+(1/3)=(5/6).
azamat

Answer:

x = 1

Step-by-step explanation:

Given equation:

\frac{x}{2}+\frac{1}{3}=\frac{5}{6}

Now,

subtracting  \frac{1}{3} from both sides

we get

⇒ \frac{x}{2}+\frac{1}{3}-\frac{1}{3}=\frac{5}{6}-\frac{1}{3}

or

⇒ \frac{x}{2}+0=\frac{5}{6}-\frac{1}{3}

or

⇒  \frac{x}{2}=\frac{5\times3-6}{6\times3}

or

⇒ \frac{x}{2}=\frac{9}{18}

or

\frac{x}{2}=\frac{1}{2}

Now, multiplying both sides with the number 2, we get

x = 1

4 0
3 years ago
Defective components: A lot of 9 components contains 4 that are defective. Two components are drawn at random and tested. Let A
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8 0
2 years ago
You paint 13 1 3 of a wall in 14 1 4 hour. At that rate, how long will it take you to paint one wall?
Lady bird [3.3K]

Find the rate at which you work, that is, the # of walls painted per hour:

13 1/3 walls          40/3

------------------  = ---------- wall per hour

14 1/4 hr              57/4

Keep 40/3 as it is; invert the divisor (57/4) and then multiply the result by 40/3:

40        4        160 wall

------ * ------  = --------------- = approx. 0.94 wall in one hour, or 160/171 wall / hr

  3       57        171 hr

4 0
3 years ago
Read 2 more answers
write an equation in point slope form of the line that passes through the point (5/6 , 0) and has a slope of m=-3
lyudmila [28]

(\stackrel{x_1}{\frac{5}{6}}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-3}(x-\stackrel{x_1}{\frac{5}{6}})

8 0
2 years ago
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