Answer:
Given that a polynomial has a constant term and at least one other term what is the minimum number of possible zero values based on the rational zero test? a-0 b-2 c-3 d-4
Answer:
Sorry this is late and I think this is right.
They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.
For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:
<em>y < - 1/2x -3</em>
<em>y > 1/2x + 2</em>
<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.
I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.
Answer:
x^2-x+3
Step-by-step explanation:
You factor it out which would then make it
(x-4)(x^2-x+3)/x-4
Then you cancel out the common factor, x-4
which leaves you with x^2-x+3
