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7nadin3 [17]
3 years ago
13

general admission tickets to the fair cost $3.50 per person rides pass cost an additional $5 and fifty per person parking cost $

6 for the family the total cost of the ride passes and parking was $51 how many people in the family attended the fair
Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

Total people x,

then, 3.5x + 5.5x + 6 = 51

simplify, 9x +6 = 51

subtract 6 on both sides, 9x= 45

divide by 9 on both sides, x= 5

therefore, total 5 people in the family.

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It's geometry, not really sure what to do
Grace [21]

Answer:

K'= (-1,-1)

J'= (-1,-5)

L'= (0,-3)

Step-by-step explanation:

What you do here is, input the (x,y) coordinates into the translation.

For example, the original point K is (-3,5). Insert this into the translation.

(-3,5) → (-3+2, 5-8) = (-1,-3)

Repeat this for the next coordinates of L and J.

J= (-3,3)

(-3,3) → (-3+2, 3-8) = (-1,-5)

L= (-2, 5)

(-2, 5) → (-2+2, 5-8) = (0,-3)

5 0
3 years ago
Brayden is going to invest in an account paying an interest rate of 4.3% compounded
Julli [10]

Answer:

810

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
8 0
3 years ago
Find the measure of angle A.<br><br> 71° x+49<br> +72
slega [8]

Answer: 66 degrees

Step-by-step explanation:

Sum of the angle measures is 180, so:

71 + x + 49 + x + 72 = 180

2x + 192 = 180

2x = -12

x = -6

Meaning the measure of angle A = -6 + 72 = 66 deg.

5 0
3 years ago
Find x<br><br> show steps too please<br><br> will give brainliest
9966 [12]

Hello from MrBillDoesMath!

Answer:   x = 7/10

Discussion:

To eliminate fractions multiply each side by 10:

10 ( 9/5x - 2/5 )  = 10 * ( 8x +3)/10      or

10 * ( 9/5)x - 10 *(2/5)  =   8x + 3  or

9 *2 x - 2*2 = 8x +3   or

18x - 4 = 8x + 3.  Subtract 8x for each side:

18x - 8x - 4 = (8x - 8x) + 3 or

10x -4 =  0x + 3 or

10x -4 = 3 or

10x = 7

x = 7/10




Thank you,

MrB

7 0
4 years ago
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