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3 years ago

I JUST USED ALL MY POINTS. PLEASE SOMEONE HELP MEEEEEE! I NEED HELP LIKE ASAP! PLEASE HELP! ;(

Mathematics

1 answer:

Marat540 [252]3 years ago

5 0

Answer
The lower quartile for the data

hope it helps

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What is 5+5 jfkkckdndnd

mario62 [17]

5+5 is ten............

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3 years ago

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What’s the equation of the blue line??

Sholpan [36]

Answer:

y = -1/2 + 2 (Slope intercept)

Step-by-step explanation:

Y-intercept is when the x-value is 0.

So the y-intercept is (0, 2)

To find slope, find two random points:

(0, 2) , (2, 1)

Slope (m) =ΔY/ΔX = -1/2 = -0.5

Equation of the line:

y = -0.5x + 2

y = -1/2 + 2

When x=0, y = 2

When y=0, x = 4

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2 years ago

Which line is perpendicular to the line y=-1/3x-2 and passes through point (1,4)

xxMikexx [17]

Answer:

Option 3) y = 3x+1

Step-by-step explanation:

Given equation is:

y = $-\frac{1}{3} x -2$

Perpendicular => It will have a slope of negative reciprocal to this slope

So the ⊥ line has a slope = m = 3

Now,

Point = (x,y) = (1,4)

So, x = 1, y = 4

Putting this in slope intercept form to get b

=> $y = mx+b$

=> 4 = (3)(1) + b

=> b = 4-3

=> b = 1

Now, Putting m and b in the slope intercept form to get the required equation:

=> y = 3x+1

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3 years ago

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zheka24 [161]

It is the third bubble
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3 years ago

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A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

2 years ago