The largest number of different whole numbers that can be on Zoltan's list is 999
<h3>How to determine the largest number?</h3>
The condition is given as:
Number = 1/3 of another number
Or
Number = 3 times another number
This means that the list consists of multiples of 3
The largest multiple of 3 less than 1000 is 999
Hence, the largest number of different whole numbers that can be on Zoltan's list is 999
Read more about whole numbers at:
brainly.com/question/19161857
#SPJ1
Do distributed property
7/3+3(2/3-1/3)^2
7/3+3×(2/3-1/3)^2
7/3+3×(1/3)^2
7/3×3×1/9
7/3×1/3
7+1/3
8/3 or 2 and 2/3 or 2.66667
Answer: 24.34 is his balance.
Step-by-step explanation:
Option A. 150 m 3 is the correct one
Answer: Choice B
95 - 1080n for any integer n
=================================================
Explanation:
Notice how 1080 is a multiple of 360 since 360*3 = 1080. The other values 1450, 780 and 340 are not multiples of 360. For example 1450/360 = 4.02777 approximately. We need a whole number result to show it is a multiple.
Therefore, choice B shows subtracting off a multiple of 360 from the original angle 95. In my opinion, it would be better to write 95+360n or 95-360n to make it more clear we are adding or subtracting multiples of 360.
Choice B will find coterminal angles, but there will be missing gaps. One missing coterminal angle is 95-360 = -265 degrees. So again, 95-360n is a more complete picture. I can see what your teacher is going for though.
