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2 years ago

What is 11% of 96 students

Mathematics

1 answer:

zaharov [31]2 years ago

7 0

Answer:

8.7

Step-by-step explanation:

8.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.7

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Scotty buys 10 bananas for $15. At this rate, how much will Scotty pay for 3 bananas?

ivolga24 [154]

Find what each banana costs by dividing the $15 dollars between the 10 bananas 15/10=$1.5 then times by 3 to get how much 3 bananas cost $1.5*3= $4.50

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2 years ago

The first one is brainlyist

bearhunter [10]

Answer:

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6 0

2 years ago

Can someone help me answer this answer and explanation plz I’ll give your brainlist and points

JulijaS [17]

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3 years ago

4. Is rap music more popular among young Indians than among young Asians? A sample survey compared 634 randomly chosen Indians a

bulgar [2K]

Answer:

H0 is accepted

there is no difference between the proportions of Indian and Asian young people who listen to rap music every day.

Step-by-step explanation:

Given a sample survey compared 634 randomly chosen Indians aged 15 to 25 with 567 randomly selected Asians in the same age group.

$p_{1} = \frac{368}{634} =0.580$

It found that 368 of the Indians and 130 Asians listened to rap music every day.

$p_{2} = \frac{130}{567} =0.229$

Null hypothesis H0: there is no difference between the proportions of Indian and Asian young people who listen to rap every day.

$p_{1} = p_{2}$

Alternative hypothesis:- $p_{1} \neq p_{2}$

Level of significance α = 0.05

The test of statistic

$z = \frac{p_{1} - p_{2}}{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} }) } } }$

where $p = \frac{n_{1}p_{1} + n_{1}p_{2}}{n_{1}+n_{2}} = \frac{634(0.580)+567(0.229)}{634+567}$

p = 0.414

and q = 1-p = 1- 0.414 =0.586

$Z = \frac{0.580-0.229}{\sqrt{0.414(0.586)(\frac{1}{634} +\frac{1}{567} } } }$

on calculation , we get

z = 0.300 ><1.96 at 95 % level of significance

H0 is accepted

there is no difference between the proportions of Indian and Asian young people who listen to rap every day.

3 0

3 years ago

Bob wants to create two pens, as shown in the figure. One pen is for a garden and it needs a heavy duty fence to keep out the cr

sattari [20]

$\bf \textit{the area of either pen is 2744, thus}\\\\
A=xy\implies 2744=xy\implies \cfrac{2744}{x}=y$

$\bf \begin{array}{llll}
\textit{perimeter of the garden pen}\\\\
P=2(x+y)\\\\
P=2\left( x+ \cfrac{2744}{x}\right)\\\\
P=2x+\cfrac{5488}{x}\\
----------\\

\textit{cost of it}\\\\
C=15\left( 2x+\cfrac{5488}{x} \right)\\\\
C=30x+\cfrac{82320}{x}
\end{array}\qquad 
\begin{array}{llll}
\textit{perimeter of the dog pen}\\\\
P=2x+y\\\\
P=2x+\cfrac{2744}{x}\\
----------\\
\textit{cost of it}\\\\
C=5\left( 2x+\cfrac{2744}{x} \right)\\\\
C=10x+\cfrac{27440}{x}
\end{array}$

notice... the dog's pen perimeter, does not include the side that's bordering the garden's, since that side will use the heavy duty fence, instead of the light one

so, the sum of both of those costs, will be the C(x)

$\bf C(x)=\left( 30x+\cfrac{82320}{x} \right)+\left( 10x+\cfrac{27440}{x} \right)
\\\\\\
C(x)=40x+\cfrac{109760}{x}$

so, just take the derivative of it, and set it to 0 to find the extremas, and do a first-derivative test for any minimum

8 0

3 years ago