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Mice21 [21]
3 years ago
13

Which algebraic expression is a polynomial with a degree of 3? 4x3 – 2y3 + 5y2 – 5y 3y3 – –xy

Mathematics
2 answers:
mash [69]3 years ago
5 0
This is the concept of algebra, given a polynomial with one variable like x and y, the degree is the largest exponent of the variable;
Given the expressions;
4x^3-2y^3+5y^2-5y The polynomial has a degree of 3 (both y and x have an exponent of 3)
3y3--xy=3y^3+xy The polynomial has a degree of 3 also (y has an exponent of 3)
Nutka1998 [239]3 years ago
5 0

Answer:

The answer is B

Step-by-step explanation:

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Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro
tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation  

n=2700 represent the random sample taken    

X represent the people in England who are deficient in Vitamin D

\hat p=0.2 estimated proportion of England people who are deficient in Vitamin D

\alpha=0.02 represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)    

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

And replacing into the confidence interval formula we got:

0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182

0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0
3 years ago
What do the Nineteenth Amendment and the Indian Citizenship Act of 1924
lana66690 [7]

Answer:

D

Step-by-step explanation:

Suffrage is the right to vote, and the nineteenth amendment gave women the right to vote, and the indian citizenship act of 1924 gave native americans the right to vote

3 0
3 years ago
What is the answer to <br> 72 divide 0.75
Alex Ar [27]

Answer:

96

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Marissa deposited $900 in her savings account. The rate of simple interest is 5% per year. Find the balance at the end of 4 year
kotegsom [21]
If you multiply the 9 in the 900 by 5 you get 45 which is 5% of 900, multiply that by 4 gives 180 so she should have $180
4 0
3 years ago
A gym has 563 people that want to attend workout classes. Each class will have 15 people.
Dmitrij [34]

40

why?: 563/15=37.53333333

Round up to the nearest 10

Brainliest?

3 0
3 years ago
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